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Lynna [10]
3 years ago
12

Which substance has a melting point greater than room temperature

Chemistry
1 answer:
yarga [219]3 years ago
7 0
The answer is b because Heating water makes it evaporate faster
Adding salt makes it boil at a higher temperature
Increasing the pressure would force the water from the air back into the beaker
Increasing the humidity means there are more molecules in the air, increasing the chance that our water
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Entrance Question: What is a physical trait? Explain using complete sentences.
azamat

Answer: A physical trait is a defining aspect or feature of your body or other subject that you can see visually.

Explanation:

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acetone and ethanol Choose one or more: A. London dispersion B. dipole–dipole C. hydrogen bonding D. ion-induced dipole
andreyandreev [35.5K]

Explanation:

The weak intermolecular forces which can arise either between nucleus and electrons or between electron-electron are known as dispersion forces. These forces are also known as London dispersion forces and these are temporary in nature.

Dipole-dipole interactions are defined as the interactions that occur when partial positive charge on an atom is attracted by partial negative charge on another atom.

When a polar molecules produces a dipole on a non-polar molecule through distribution of electrons then it is known as dipole-induced forces.

Hydrogen bonding is defined as a bonding which exists between a hydrogen atom and an electronegative atom like O, N and F.

Chemical formula of acetone is CH_{3}COCH_{3}. Due to the presence of oxygen atom there will be partial positive charge on carbon and a partial negative charge on oxygen atom. Hence, dipole-dipole forces will exist in a molecule of acetone.

Whereas hydrogen bonding will exist in a molecule of ethanol (CH_{3}CH_{2}OH). Since, hydrogen atom is attached with electronegative oxygen atom.

Whereas London dispersion forces will also exist in both acetone and ethanol molecule.

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3 years ago
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8 0
3 years ago
Read 2 more answers
a. The student uses the same sodium hydroxide to titrate 10.00-mL of vinegar to a phenolphthalein end point. If the titration re
lana66690 [7]

Answer:

a) If the titration required 21.84 mL of sodium hydroxide, NaOH (aq), calculate the molar concentration of the sodium hydroxide solution, NaOH (aq). (Remember that KHP is potassium hydrogen phthalate, KHC8H4O4, NOT potassium hydrogen phosphorus!)

b) The student uses the same sodium hydroxide to titrate 10.00 mL of vinegar to a phenolphthalein end point. If the titration required 27.48 mL of sodium hydroxide, NaOH (aq), calculate the molar concentration of acetic acid, HC2H3O2 (aq), in the vinegar.

c) Calculate the mass percent of acetic acid, HC2H3O2(aq), in the vinegar using the molar concentration for acetic acid, HC2H3O2 (aq), determined in part b and assuming the density of the solution is 1.01 g/mL.

Explanation:

a) If the titration required 21.84 mL of sodium hydroxide, NaOH (aq), calculate the molar concentration of the sodium hydroxide solution, NaOH (aq). (Remember that KHP is potassium hydrogen phthalate, KHC8H4O4, NOT potassium hydrogen phosphorus!)

b) The student uses the same sodium hydroxide to titrate 10.00 mL of vinegar to a phenolphthalein end point. If the titration required 27.48 mL of sodium hydroxide, NaOH (aq), calculate the molar concentration of acetic acid, HC2H3O2 (aq), in the vinegar.

c) Calculate the mass percent of acetic acid, HC2H3O2(aq), in the vinegar using the molar concentration for acetic acid, HC2H3O2 (aq), determined in part b and assuming the density of the solution is 1.01 g/mL.

5 0
2 years ago
What us the % composition of oxygen (O) in iron (III) hydroxide, Fe(OH)<br> 3?
S_A_V [24]

Answer:

44.91% of Oxygen in Iron (III) hydroxide

Explanation:

To solve this question we must find the molar mass of Fe(OH)3 and the molar mass of the oxygen in this molecule. Percent composition will be:

<em>Molar mass Oxygen / molar mass Fe(OH)3 * 100</em>

<em />

<em>Molar mass Fe(OH)3 and oxygen:</em>

1Fe = 55.845g/mol*1 = 55.845

3O = 16.00g/mol*3 = 48.00 - Molar mass of Oxygen

3H = 1.008g/mol*3 = 3.024

55.845 + 48.00 + 3.024 =

106.869g/mol is molar mass of Fe(OH)3

% Composition of oxygen is:

48.00g/mol / 106.869g/mol * 100 =

<h3>44.91% of Oxygen in Iron (III) hydroxide</h3>
7 0
3 years ago
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