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MA_775_DIABLO [31]
2 years ago
7

The electric potential, VVV, in volts, between two metal plates a distance of ddd millimeters from the left plate is given by th

e equation above when 0 \le d \le 150≤d≤150, is less than or equal to, d, is less than or equal to, 15. By how many millimeters does the distance from the left plate increase for the potential to increase by 111 volt? Answer:
Mathematics
2 answers:
LenKa [72]2 years ago
4 0

V is the voltage or the potential difference between the plates, usually expressed in volts.

Infinite parallel plates have a uniform electric field between them.  

So V = 245 (V/m) * 0.0037 (m) = 0.9065 volts

Evgen [1.6K]2 years ago
4 0

Answer:

The distance from the left plate increases by 3 mm for the potential to increase by 1 volt.

Step-by-step explanation:

The complete Question is

V = -2.6 + (d/3)

The electric potential, V, in volts, between two metal plates a distance of d millimetres from the left plate is given by the equation above when 0≤d≤15. By how many millimetres does the distance from the left plate increase for the potential to increase by 1 volt?

Mathematically, the derivative of d with respect to V is equal to the ratio of small changes in d divided by small changes V.

(dd/dV) = (Δd/ΔV)

Δd = (dd/dV) × ΔV

V = -2.6 + (d/3)

(d/3) = V + 2.6

d = 3V + 7.8

(dd/dV) = 3

Δd = (dd/dV) × ΔV

(dd/dV) = 3 mm/volt

ΔV = 1 volt

Δd = 3 × 1 = 3 mm

Hope this Helps!!!!

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