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Margarita [4]
3 years ago
9

If a right circular cone intersects a plane that runs parallel to the edge of the cone, the resulting curve will be a

Mathematics
2 answers:
gulaghasi [49]3 years ago
5 0

If a right circular cone intersects a plane that runs parallel to the edge of the cone, the resulting curve will be a <u>parabola</u>.

A parabola is curved from one end and open from other end, therefore it would fit the best.

Hope I could help! :)

slega [8]3 years ago
4 0
<h2>Answer:</h2>

If a right circular cone intersects a plane that runs parallel to the edge of the cone, the resulting curve will be a:  Parabola.

<h2>Step-by-step explanation:</h2>
  • If a plane is perpendicular to the axis of rotation of the cone then the resulting cross section will be a <em>Circle.</em>
  • If the plane is placed slightly tilted across the axis of rotation of the cone then the resulting cross section will be a<em>  Ellipse.</em>
  • If a plane is placed such that it is parallel to the side of the cone i.e. the edge of a cone then the resulting cross section is <em>Parabola.</em>
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The product of the expression (\frac{4k+2}{k^2-4})* \frac{k-2}{2k+1}  is the expression \frac{2}{k+2}

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Given the expression:

(\frac{4k+2}{k^2-4})* \frac{k-2}{2k+1} \\\\This\ can\ be\ simplified\ to:\\\\(\frac{2(2k+1)(k-2)}{(k+2)(k-2)(2k+1)}) \\\\=\frac{2}{k+2}

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