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3 years ago

Identify the property that the statement illustrates, 6 x 4 = 4 x6

Mathematics

2 answers:

nadezda [96]3 years ago

8 0

Plz give brainliest

ANSWER:

Commutative Property

Vesna [10]3 years ago

4 0

Answer:

Symmetrical Property.

Step-by-step explanation:

(self-explanatory)

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Step-by-step explanation:

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What is the value of x in the equation 4x - 6+32(-2x+4)=3x -(x+4)?

Lina20 [59]

I think -2 is the answer

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3 years ago

Pls help answer will give brainliest

sweet [91]

Answer:

Step-by-step explanation:

Let x be the number.

Sum of five and 8 times a number: 8x + 5

Fifty plus one half of the number: 50 + (1/2)x

$8x+5=50+\frac{1}{2}x\\\\8x+5-5=50+\frac{1}{2}x-5\\\\8x=45+\frac{1}{2}x\\\\8x-\frac{1}{2}x=45\\\\\frac{16x}{2}-\frac{1}{2}x=45\\\\\frac{16x-x}{2}=45\\\\\frac{15x}{2}=45\\\\x=45*\frac{2}{15}\\\\x=3*2\\\\x=6$

3 0

4 years ago

At a new exhibit in the museum of science, people are asked to choose between 90 or 120 random draws from a machine. The machine

Serga [27]

Answer:

There is a probability of P₉₀=0.09853 of winning the prize with a 90-balls sample.

There is a probability of P₁₂₀=0.0853 of winning the prize with a 120-balls sample.

Step-by-step explanation:

In this problem, the balls that are removed are then replaced in the total, so the probability of obtaining a green ball is constant and is equal to:

$P_g=\frac{93}{93+65}= 0.5886$

This type of sampling should be analyzed with the binomial distribution, but given the sample size, it is convenient to use the approximation to a normal distribution.

The parameters of the normal distribution are:

$\mu=P_g*n=0.5886*90=52.9746\\\\\sigma=\sqrt{np(1-p)}=\sqrt{90*0.5886*(1-0.5886)} =4.6684$

To win the prize it is needed at least 65% of green balls in the sample, which means there have to be at least 59 green balls in the sample:

$0.65*90=58.5$

To calculate the probability of getting 59 or more green balls, we have to calculate the z-value

$z=\frac{x-\mu}{\sigma}=\frac{59-52.9746}{4.6684}= 1.29$

Then, the probability can be look up with the z-value in a normal distribution table:

$P(X \geq 59)=P(z\geq 1.29)=0.09853$

There is a probability of P=0.09853 of winning the prize with a 90-balls sample.

When the sample is of 120 balls, we have to recalculate the parameters.

Normal distribution

$\mu=P_g*n=0.5886*120=70.6320\\\\\sigma=\sqrt{np(1-p)}=\sqrt{120*0.5886*(1-0.5886)} =5.3905$

To win the prize it is needed at least 65% of green balls in the sample, which means there have to be at least 78 green balls in the sample:

$0.65*120=78$

To calculate the probability of getting 78 or more green balls, we have to calculate the z-value

$z=\frac{x-\mu}{\sigma}=\frac{78-70.6320}{5.3905}=1.37$

Then, the probability can be look up with the z-value in a normal distribution table:

$P(X \geq 78 )=P(z\geq 1.37)=0.0853$

There is a probability of P=0.0853 of winning the prize with a 120-balls sample.

8 0

3 years ago