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Svetlanka [38]
3 years ago
7

Give 3 examples, from the lab, where potential energy was converted to kinetic energy.

Physics
1 answer:
Stella [2.4K]3 years ago
6 0

1. The red ball was potential energy until it was hit by the pendulum converting into kinetic energy.

2. The 5 pounds was a potential energy, until the rope was cut by the scissors, this made the 5 pounds become kinetic energy.

3. The bucket was a potential energy, till the books landed in it causing it to fall, this became kinetic energy

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Some steamboat restaurants use paper pots for their customers to boil the food themselves. What is the reason for the paper not
Ber [7]

Answer: D. 1,2,3 

The paper pots used in steamboat restaurants will not catch fire when in contact with the flame for the heat is conducted quickly to the water because the paper is thin and the burning temperature of the paper is much higher than the boiling point of water. Lastly, the texture of the paper is thick that it can withstand the temperature of the flame.

 

7 0
4 years ago
Suppose that you are standing on a train accelerating at 0.20g (where g is the acceleration due to gravity). What minimum coeffi
prisoha [69]

Answer:

0.2

Explanation:

The given parameters are;

The acceleration of the train, a = 0.2·g

The mass of the person standing on the train = m

Let μ represent the coefficient of static friction, we have;

The force acting on the person, F = m × a = m × 0.2·g

The force of friction acting between the feet and the floor, F_f = m·g·μ

For the person not to slide we have;

The force acting on the person = The force of friction acting between the feet and the floor

F = F_f

∴ m × 0.2·g = m·g·μ

From which we get;

0.2 = μ

The coefficient of static friction that must exist between the feet and the floor if the person is not to slide, μ = 0.2.

7 0
3 years ago
a motorcycle accelerates from 15 m/s to 20 m/s over a distance of 50 meters. what is its average acceleration?
devlian [24]
For this, you need the v-squared equation, which is v(final)² = v(initial)² + 2aΔx The averate acceleration is thus a = (v(final)² - v(initial)²) / 2Δx = (20² - 15²) / 2(50) = 175 / 100 = 1.75 m/s² So the average acceleration is 1.75 m/s²
5 0
4 years ago
Imvu?<br> ..............................
Dominik [7]
Imvu? Like the app?
4 0
3 years ago
Read 2 more answers
Can you please answers these for me please today is the last day to turn in work and I need this to pass please I’m begging than
Ymorist [56]

Answer:

1.   <u>F = ma</u>  <em>F = 0.2kg * 20m/s² = 4Kg * m/s² =</em> 4N

2.  <u>F = ma</u>  <em>F - 18Kg * 3m/s² = 54Kg * m/s² =</em> 54N

3.  <u>F = ma</u>  <em>F = 0.025Kg * 5m/s² =</em> 0.125N

4.  <u>F = ma</u>  <em>F = 50Kg * 4m/s² =</em> 200N

5.  <u>F = ma</u>  <em>F = 70Kg * 4m/s² =</em> 280N

6.  <u>F = ma</u>  <em>F = 9Kg * 9.8m/s² =</em> 88.2N

Explanation:

Hope this helps ! ^^

8 0
3 years ago
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