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Artemon [7]
2 years ago
14

A resistor is connected to a 36v power supply. An ammeter measures a current of 2.0 A going through it. Determine the resistance

in ohm
Physics
1 answer:
m_a_m_a [10]2 years ago
8 0

R = 18 ohms

Explanation:

Given:

V = 36 volts

I = 2.0 A

R = ?

Use Ohm's law to solve for the resistance:

V = IR

or

R = V/I

= (36 volts)/(2.0 A)

= 18 ohms

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State coulomb's law mathematically
Vsevolod [243]

Coulomb's law is express as:

\begin{gathered} F=k\frac{q_1q_2}{r^2} \\ \text{ where} \\ k\text{ is Coulomb's constant} \\ q_1\text{ and }q_2\text{ are the charges} \\ r\text{ is the distance between charges} \end{gathered}

7 0
11 months ago
A proton that has a mass m and is moving at +164 m/s undergoes a head-on elastic collision with a stationary carbon nucleus of m
Irina18 [472]
The concept of this problem is the Law of Conservation of Momentum. Momentum is the product of mass and velocity. To obey the law, the momentum before and after collision should be equal:

m₁ v₁ + m₂v₂ = m₁v₁' + m₂v₂', where
m₁ and m₂ are the masses of the proton and the carbon nucleus, respectively,
v₁ and v₂ are the velocities of the proton and the carbon nucleus before collision, respectively,
v₁' and v₂' are the velocities of the proton and the carbon nucleus after collision, respectively,

m(164) + 12m(0) = mv₁' + 12mv₂'
164 = v₁' + 12v₂'  --> equation 1

The second equation is the coefficient of restitution, e, which is equal to 1 for perfect collision. The equation is

(v₂' - v₁')/(v₁ - v₂) = 1
(v₂' - v₁')/(164 - 0) = 1
v₂' - v₁'=164 ---> equation 2

Solving equations 1 and 2 simultaneously, v₁' =  -138.77 m/s and v₂' = +25.23 m/s. This means that after the collision, the proton bounced to the left at 138.77 m/s, while the stationary carbon nucleus move to the right at 25.23 m/s.
7 0
3 years ago
A long, straight metal rod has a radius of 5.75 cm and a charge per unit length of 33.3 nC/m. Find the electric field at the fol
PIT_PIT [208]

Answer:

Explanation:

From the question;

We will make assumptions of certain values since they are not given but the process to achieve the end result will be the same thing.

We are to calculate the following task, i.e. to determine the electric field at the distances:

a)  at 4.75 cm

b)  at 20.5 cm

c) at 125.0 cm

Given that:

the charge (q) = 33.3 nC/m

= 33.3 × 10⁻⁹ c/m

radius of rod = 5.75 cm

a) from the given information, we will realize that the distance lies inside the rod. Provided that there is no charge distribution inside the rod.

Then, the electric field will be zero.

b) The electric field formula E = \dfrac{kq }{d}

E = \dfrac{9 \times 10^9 \times (33.3 \times 10^{-9}) }{0.205}

E = 1461.95 N/C

c) The electric field E is calculated as:

E = \dfrac{9 \times 10^9 \times (33.3 \times 10^{-9}) }{1.25}

E = 239.76 N/C

7 0
3 years ago
What is average speed?what is the formula for average speed?what does it mean?
Rama09 [41]
Average speed = total distance traveled/total time taken
it is the total distance traveled in a total time the total distance is attained
4 0
3 years ago
Background information about reflection and refraction of light
KIM [24]

Answer:

reflection :

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  • Incident ray and reflect d ray plus normal lies on the same plan on a same point
  • light reflect uniformly if it is incident on a plan surface

refraction :

  • light will refrect if light goes from rare medium to a dense medium or vice versa
  • after the light is refracted, it retunes to its original direction
  • angle of incidence is not equal to the angle of refraction
4 0
3 years ago
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