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evablogger [386]
3 years ago
15

Find the coordinates of the point (x,y,z)(x,y,z) on the plane z=2x+3y+3z=2x+3y+3 which is closest to the origin.

Mathematics
1 answer:
Ainat [17]3 years ago
4 0
The vector equation of the line through the origin perpendicular to the plane is
.. (x, y, z) = t(2, 3, -1)
so the point of interest will satisfy
.. 2(2t) +3(3t) -(-t) = -3
.. 14t = -3
.. t = -3/14
and its coordinates are (x, y, z) = (-3/7, -9/14, 3/14)
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NEEd help! Will help alot tysm!
xz_007 [3.2K]

Answer:

3rd one

Step-by-step explanation:

7 0
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<h3>Standard form equation of a quadratic function.</h3>

It follows from the task content that the standard form equation of the quadratic function is to.be determined.

Since the standard form equation can be derived from the vertex form equation as follows;

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Hence, to find the value of a, Substitute x = 8 and f(x) = -11 so that we have;

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Read more on quadratic functions;

brainly.com/question/25841119

#SPJ1

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