Answer:
% Mass of sand = 35.95%
% Mass of KBr = 64.05%
Explanation:
From the question given, we obtained the following:
Mass of mixture( KBr + sand) = 10g
Mass of sand = 3.595g
Mass of KBr = 10 — 3.595 = 6.405g
% Mass of sand = ( Mass of sand / mass of mixture) x 100
% Mass of sand = (3.595 / 10) x100
% Mass of sand = 35.95%
We can obtain the percentage of KBr by subtracting the percentage of sand from 100. This is illustrated below:
% Mass of KBr = 100 — 35.95
% Mass of KBr = 64.05%
Answer:
Option C. 52.057
Explanation:
The following data were obtained from the question:
Isotope >> Mass number > Percentage
A (Cr-50) > 50 >>>>>>>>>> 4.3
B (Cr-52) > 52 >>>>>>>>>> 83.8
C (Cr-53) > 53 >>>>>>>>>> 9.5
D (Cr-54) > 54 >>>>>>>>>> 2.4
Average atomic mass =?
The average atomic mass of chromium, Cr can be obtained as follow:
Average atomic mass = [(Mass of A × A%) /100] + [(Mass of B × B%) /100] + [(Mass of C × C%) /100] + [(Mass of D × D%) /100]
Atomic mass of Cr = [50×4.3)/100] + [52×83.8)/100] + [53×9.5)/100] + [54×2.4)/100]
= 2.15 + 43.576 + 5.035 + 1.296
Atomic mass of Cr = 52.057
Therefore, the atomic mass of chromium, Cr is 52.057
Answer:
The Weight
Explanation:
Even know it has the same volume does not mean it has the same mass and weighs the same with the items inside the box. Most likely, that the Items inside the box are heavier then the first box Max moved.
A. 0.02 mol of O2
B. 0.1 mol of CI2
C. 1 mol of N2
D. 2 mol of H2
Bolded answer is correct.
