What is the area of the given regular polygon?
1 answer:
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Answer:
X-5Y-4Z+12=0
Step-by-step explanation:
Plan P1 = 3x-y+2z=1. with A=(1,1,2); B=(2,2,1); we must will find V1 from P1,
V1 =(3,-1,2) and AB = (2-1,2-1,1-2) = (1,1,-1) now we find V2 by vector product.
V2 =V1.X,AB =; (aplying sarrus method)
according to general plan formula a(X-Xo)+b(Y-Yo)+c(Z-Zo); V=(a,b,c)
V2=(-1,5,4) ; A=(1,1,2); so -(X-1)+5(Y-1)+4(z-2)=0 → -X+1+5Y-5+4Z-8=0 →
-X+5Y+4Z+1-5-8=0 → -X+5Y+4Z-12=0 (-1) → Plan equation X-5Y-4Z+12=0
Total = 500 * (1 + .06/12) ^ 12 * 4
Total = 500 * (1.005) ^ 48
Total = 500 * <span> <span> <span> 1.2704891611 </span> </span> </span> <span> </span>
Total =635.24
Total = 500 * (1.005) ^ 48
Total = 500 * <span> <span> <span> 1.2704891611 </span> </span> </span> <span> </span>
Total =635.24