Which equation will be parallel to y=6 A)Y= -6x B)X=6 C)y=1 D)Y=6x

A construction company is strung up signs on 4 mile of the road.. if the company places a sign every 1/8 of a mile, how many sig

koban [17]

"A construction company is stringing up signs ... "

Divide 4 miles by 1/8 mile:

4 miles

--------------------------- = 32 signs are needed

(1/8) mile per sign

6 0

3 years ago

MAKE YOU THE BRAINLIEST EASY QUESTION Show the formula for finding the area of a triangle. Then find the area of a right triangl

lesya692 [45]

Answer:

Formula to find the area of a triangle is 1/2(bxh). The area of the right triangle is 28.

Step-by-step explanation:

To solve this problem you would plug in the base and height into the formula and follow the order of operations (P.E.M.D.A.S). So the equation would then read 1/2(5x11.2). Once you solve inside the parenthesis, the equation then reads, 1/2(56). Then you solve what half of 56 is, which is 28.

I hoped this helped you!

6 0

2 years ago

Read 2 more answers

85.87 J or heat energy is added to a 34.8 g mass of substance the temperature rises from 21.76°C

Andru [333]

Answer:

The required specific heat is 196.94 joule per kg per °C

Step-by-step explanation:

Given as :

The heat generated = Q = 85.87 J

Mass of substance (m)= 34.8 gram = 0.0348 kg

Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C

Let the specific heat = S

Now we know that

Heat = Mass × specific heat × change in temperature

Or, Q = msΔt

Or, 85.87 = (0.0348 kg ) × S × 12.53°C

Or , 85.87 = 0.4360 × S

Or, S = $\frac{85.87}{0.4360}$

∴ S = 196.94 joule per kg per °C

Hence the required specific heat is 196.94 joule per kg per °C Answer

7 0

2 years ago

Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li

krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

$A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years$

First, let us calculate the decay constant (k)

$75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036$

Next, let us calculate the half-life as follows:

$\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2} \approx 669\ years$

Therefore the half-life is between 600 and 700 years

5 0

2 years ago

rachel got prepaid debit card with $30 on it. For her first purchase with the card, she bought some bulk ribbon at a craft store

Tanya [424]

Answer:

46 yards.

Step-by-step explanation:

Subtract the new balance from the original balance:

30.00 - 19.88 = 10.12

Therefore, Rachel spent $10.12

Divide the result by the cost of ribbons per yard:

10.12 ÷ 0.22 = 46

Therefore, Racheal bought 46 yeards of ribbon.

5 0

1 year ago