Given:
Figures A, B and C.
To find:
The order of the figures and volume of each figure.
Solution:
<u>Figure A:</u>
Length = 10, Width = 2 and Height = 2
Volume of A = length × width × height
= 10 × 2 × 2
Volume of A = 40 cubic units
<u>Figure B:</u>
Length = 3, Width = 3 and Height = 1
Volume of B = length × width × height
= 3 × 3 × 1
Volume of B = 9 cubic units
<u>Figure C:</u>
Length = 6, Width = 3 and Height = 3
Volume of C = length × width × height
= 6 × 3 × 3
Volume of C = 54 cubic units
Order from greatest to least:
54 < 40 < 9
C < A < B
Hence Kurry said the correct answer.
60.7, 60.17, 60.1, 60.07, 60.007
Answer:
cos 2 x=1-sin^2 x
Step-by-step explanation:
x=-135°
cos 2x=cos (-270)=cos (-270+360)=cos 90=0
or cos 2x=1-2sin ²x=1-2(sin (-135))²
=1-2(-sin 135)²
=1-2(sin 135)²
=1-2(sin (180-45))²
=1-2(sin²45)
=1-2 (\frac{1}{\sqrt{2}})²
=1-1
=0
Don't you mean, "Which is smallest of the following numbers?"
Converting all those fractions into decimal fractions would be the fastest way to go, for me at least.
0.67
0.75
1.50
0.60
2.67
0.875 It's pretty obvious that 0.60 (3/5) IS THE SMALLEST fraction here.