Over which interval is the graph of f(x) = –x2 3x 8 increasing?
2 answers:
Since you were able to type that negative, I will assume that
f(x)=-x^2+3x+8
the vertex is where the graph changes from increasing to decreasing or vice verca
find theh vertex
-b/2a is x coordinate of vertex where
f(x)=ax^2+bx+c
a=-1
b=3
-3/2(-1)=-3/-2=3/2
we see that the leading coeficient (a) is negative so the graph opens down
it increases then decreases at the vertex
so from negative infinity to 3/2 is interval
in interval nottaion
(⁻∞,3/2]
Answer:A.(-%,1.5)
Step-by-step explanation:
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Answer:
7/3
Step-by-step explanation:
in decimal 2.3
in fraction 2 1/3
Same line so the correct answer is b
I'm pretty sure this is correct
X=3, y=4
x=-2, y=9
Set x equal to anything, then isolate y to get the other number.
X * 0.85 = 136
x = 136/0.85
x = 160
hope this helps :)
