Answer:
• Gayle: 14
• Crystal: 3
Step-by-step explanation:
Let g represent the number of paperclips Gayle has. Then 42/g is the number Crystal has. The relationship between the two numbers is said to be ...
g - (42/g) = 11
Multiplying by g gives ...
g^2 -42 = 11g
g^2 -11g -42 = 0 . . . . subtract 11 g to put into standard form
To factor this, you are looking for two factors of -42 that sum to -11.
-42 = -42·1 = -21·2 = -14·3 = -7·6
You can see that -14 and 3 sum to -11, so the factoring is ...
(g -14)(g +3) = 0
g = 14 . . . . . . . . . . makes the product zero. (The g=-3 solution is extraneous.)
Gayle has 14 paperclips and Crystal has 3.
Answer:
Step-by-step explanation:
Sweet. Get to answer finally. I was the guy commenting on your other post.
1. 72
2. 46
3. 99
4. Same side interior angles are supplementary
5. alternate interior angles are equal to each other so set up the x expressions equal to each other. 5x-7=3x+17. Solve for x
5x-7=3x+17
2x=24
x=12
plug it in for the 5x-7 and get an angle.. 5(12)-7
60-7
53.
The 5x-7 and the 4y+3 is supplementary.
so 53+3+4y=180. combine the 2 and set them equal to 180 to find y
56+4y=180
124=4y
y=31
And now we find the angle of 6. We know that corresponding angles are equal and the y expression and angle 6 are corresponding angles
so plug in your answer for y in the expression..
4(31)+3 = 127.
so angle 6 is 127
I'm assuming a 5-card hand being dealt from a standard 52-card deck, and that there are no wild cards.
A full house is made up of a 3-of-a-kind and a 2-pair, both of different values since a 5-of-a-kind is impossible without wild cards.
Suppose we fix both card values, say aces and 2s. We get a full house if we are dealt 2 aces and 3 2s, or 3 aces and 2 2s.
The number of ways of drawing 2 aces and 3 2s is
and the number of ways of drawing 3 aces and 2 2s is the same,
so that for any two card values involved, there are 2*24 = 48 ways of getting a full house.
Now, count how many ways there are of doing this for any two choices of card value. Of 13 possible values, we are picking 2, so the total number of ways of getting a full house for any 2 values is
The total number of hands that can be drawn is
Then the probability of getting a full house is
You are correct with the 1.42 but wrong with the 10^5
Count the digits after the 1, which is 7. So it should be
1.42 x 10^7
