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MAXImum [283]
2 years ago
10

Kennyhas$893inasavingsaccount.The interest rate is 8 1/5%, compounded annually.

Mathematics
1 answer:
qwelly [4]2 years ago
6 0
  • Principal (P) = $ 893
  • Interest rate (r) = 8 \frac{1}{5} \% =  \frac{41}{5} \% =  \frac{41}{5 \times 100}    =  \frac{41}{500}  \\
  • Number of times the amount is compounded per time period (n) = 1
  • Time (t) = 5 years.
  • Let the compound interest be I.
  • Therefore,

\sf \: I = P(1 +  \frac{r}{n}  {)}^{nt}  - P    \\ \sf  =  893(1 +  \frac{41}{500} ) ^{1 \times 5}  - 893 \\   \sf= 893 \times ( \frac{541}{500} ) ^{5}  - 893 \\   \sf= 1324.30 - 893 \\  \sf = 431.30

Answer:

$431.30(approximate value)

Hope you could get an idea from here.

Doubt clarification - use comment section.

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The length of a rectangle is 3 cm less than twice the width. If the perimeter is 42 cm, what is the length of the rectangle?
larisa [96]

Answer:

The length is 13

Step-by-step explanation:

w+w+l+l= perimeter

if the length is 3m less than twice the width then let's do some math.

42 divided 2 =21. so the width and length of one side have to equal 21. For example, let's use 8 as the width. The length would be twice(16) minus three(13) 13 plus 8 is 21. WOW it equals half of it so no we know the length is 13 and the wdith is 8.

6 0
3 years ago
What is the mean of 13,20,15,20
il63 [147K]

Answer:

17

Step-by-step explanation:

all 4 numbers added up, 68, divide by the amount of numbers, which is 4, and you get the answer

8 0
3 years ago
Read 2 more answers
There are 50 deer in a particular
olchik [2.2K]

answered

There are 50 deer in a particular forest. The population is increasing at a rate of 15% per year. Which exponential growth function represents

the number of deer y in that forest after x months? Round to the nearest thousandth.

1

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dribeiro

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561.4K people helped

Answer:

The expression that represents the number of deer in the forest is

y(x) = 50*(1.013)^x

Step-by-step explanation:

Assuming that the number of deer is "y" and the number of months is "x", then after the first month the number of deer is:

y(1) = 50*(1+ 0.15/12) = 50*(1.0125) = 50.625

y(2) = y(1)*(1.0125) = y(0)*(1.0125)² =51.258

y(3) = y(2)*(1.0125) = y(0)*(1.0125)³ = 51.898

This keeps going as the time goes on, so we can model this growth with the equation:

y(x) = 50*(1 - 0.15/12)^(x)

y(x) = 50*(1.013)^x

8 0
3 years ago
If C is between A and B, then answer the following if AB=40, AC= 2x+10, CB= 3x-5
Marat540 [252]

If C is between A and B, then, we can write the equation

AB = AC + CB


Substitute the value of AB and the expressions for AC and CB in terms of x.


40 = (2x+10)+(3x-5)


We can now solve for x.



40-10+5= 2x+3x



35=5x


Dividing by 5.


7=x


AB=40



AC=2(7)+10



AC=14+10



AC=24




BC=3(7)-5



BC=21-5


BC=16



6 0
3 years ago
Jose just submitted his resume to a job posting. The posting started thats the job pays $47.588 annually. What would Jose’s mont
Marrrta [24]

Answer:

3965.67 a month

Step-by-step explanation:

presuming you mean $47,588 annually.

47588/12

8 0
3 years ago
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