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MAXImum [283]
3 years ago
10

Kennyhas$893inasavingsaccount.The interest rate is 8 1/5%, compounded annually.

Mathematics
1 answer:
qwelly [4]3 years ago
6 0
  • Principal (P) = $ 893
  • Interest rate (r) = 8 \frac{1}{5} \% =  \frac{41}{5} \% =  \frac{41}{5 \times 100}    =  \frac{41}{500}  \\
  • Number of times the amount is compounded per time period (n) = 1
  • Time (t) = 5 years.
  • Let the compound interest be I.
  • Therefore,

\sf \: I = P(1 +  \frac{r}{n}  {)}^{nt}  - P    \\ \sf  =  893(1 +  \frac{41}{500} ) ^{1 \times 5}  - 893 \\   \sf= 893 \times ( \frac{541}{500} ) ^{5}  - 893 \\   \sf= 1324.30 - 893 \\  \sf = 431.30

Answer:

$431.30(approximate value)

Hope you could get an idea from here.

Doubt clarification - use comment section.

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Step-by-step explanation:

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Answer:

\boxed{r =  \frac{h}{3}  +  \frac{v}{\pi {h}^{2} } }

Step-by-step explanation:

Solve \:  for \:  r:  \\  =  >   v= \pi {h}^{2}(r -  \frac{h}{3}  ) \\  \\  v=\pi {h}^{2}(r -  \frac{h}{3}  )is \:  equivalent  \: to   \:   {h}^{2}\pi(r -  \frac{h}{3}  ) = v: \\  =  >  {h}^{2}\pi(r -  \frac{h}{3}  ) = v \\  \\ Divide  \: both \:  sides  \: by  \: \pi  {h}^{2} :  \\  =  > r -  \frac{h}{3}  =  \frac{v}{\pi {h}^{2} }  \\  \\ Add \:   \frac{h}{3}  \:  to  \: both \:  sides:  \\  =  > r =  \frac{h}{3}  +  \frac{v}{\pi {h}^{2} }

7 0
3 years ago
Please solve with working thankyou
Lisa [10]

Answer:

m∠y=72°

Step-by-step explanation:

<u><em>The question is</em></u>

Find the measure of angle y

step 1

Find the measure of angle x

see the attached figure to better understand the problem

we know that

m∠x=67° -----> by corresponding angles

step 2

Find the measure of angle y

we know that

(m∠x+m∠y)+42°=180° -----> because form a straight line

substitute the measure of angle x

67°+m∠y+42°=180

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m∠y=180°-108°

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