Ask question

Ask question

All categories

3 years ago

14

#14 this is sixth grade math using algebraic expressions

1 answer:

maw [93]3 years ago

8 0

what are the questions?

You might be interested in

This season, the probability that the Yankees will win a game is 0.5 and the probability that the Yankees will score 5 or more r

NemiM [27]

Answer:

The answer is .64

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

-5(5-3v)=-115<br> Helpp me please

prisoha [69]

we start by opening the brackets so it will be -25 plus 15 v is equals to 115. negative times a negative is a positive so -5 times -3 we we have gotten positive 15v there I hope you understood so our new equation is -25 + 15v is equals to 115 collect the like terms 15v is equals to 115 + 25 15 v is equals to 140 divide both sides by 15 so v is equals to 9 and 1/3

8 0

3 years ago

Find the slope and reduce.

saveliy_v [14]

The slope will be 4/7. Let me know if you want an explanation.
Answer: 4/7

Hope this helped!

8 0

3 years ago

Read 2 more answers

The probability that a pupil in class has a calculator is 0.87 what is the probability that a pupil does not have a calculator?

lidiya [134]

Answer:

0.87 1.0

0.13

Step-by-step explanation:

0.13 dont have a calculator

8 0

3 years ago

Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court

Ksju [112]

Answer:

$(a)\dfrac{92}{117}$

$(b)\dfrac{8}{39}$

$(c)\dfrac{25}{117}$

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>

(a)Probability that both appointees are men.

$P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}$

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed) $=P(MW)+P(WM)$

$=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}$

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.
Two women are appointed

P(at least one woman is appointed) $=P(MW)+P(WM)+P(WW)$

$P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}$

In Part B, $P(MW)+P(WM)=\frac{8}{39}$

Therefore:

$P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}$

5 0

3 years ago