You can tell if lines are perpendicular or not by seeing if meet in a right angle. A right angle is like a square, and the lines would have to be 90 degrees.
One example is when the two lines (horizontal and vertical) meet each other at the ends.
(You MUST make sure that they are directly horizontal and vertical. If not, they will either be acute or obtuse).
I hope this helped!
The x-intercept is the number without the variable.
So, #1's correct answer would be A. because -10 is not greater than -2.
Simplify \frac{21}{2}x
2
21
x to \frac{21x}{2}
2
21x
\frac{21x}{2}-\frac{3}{4}(2x+5)=\frac{3}{8}
2
21x
−
4
3
(2x+5)=
8
3
2 Simplify \frac{3}{4}(2x+5)
4
3
(2x+5) to \frac{3(2x+5)}{4}
4
3(2x+5)
\frac{21x}{2}-\frac{3(2x+5)}{4}=\frac{3}{8}
2
21x
−
4
3(2x+5)
=
8
3
3 Multiply both sides by 44 (the LCM of 2, 42,4)
42x-3(2x+5)=\frac{3}{2}42x−3(2x+5)=
2
3
4 Expand
42x-6x-15=\frac{3}{2}42x−6x−15=
2
3
5 Simplify 42x-6x-1542x−6x−15 to 36x-1536x−15
36x-15=\frac{3}{2}36x−15=
2
3
6 Add 1515 to both sides
36x=\frac{3}{2}+1536x=
2
3
+15
7 Simplify \frac{3}{2}+15
2
3
+15 to \frac{33}{2}
2
33
36x=\frac{33}{2}36x=
2
33
8 Divide both sides by 3636
x=\frac{\frac{33}{2}}{36}x=
36
2
33
9 Simplify \frac{\frac{33}{2}}{36}
36
2
33
to \frac{33}{2\times 36}
2×36
33
x=\frac{33}{2\times 36}x=
2×36
33
10 Simplify 2\times 362×36 to 7272
x=\frac{33}{72}x=
72
33
11 Simplify \frac{33}{72}
72
33
to \frac{11}{24}
24
11
x=\frac{11}{24}x=
24
11
X=11 over 24
Answer:
2,5 maybe
Step-by-step explanation:
Answer:
not sure sorry!
Step-by-step explanation:
I just need points lol
