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2 years ago

You construct a tangent to circle O at point X on the circle, as shown below. What do you expect to be the measure of ∠OXY?

Mathematics

1 answer:

Misha Larkins [42]2 years ago

8 0

Answer: 90 Degrees :)

Step-by-step explanation:

Ur Welcome ;)

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2.5 divided by 0.5 what would that be

Alex17521 [72]

Answer:

1.25

Step-by-step explanation:

1/2 of 2.5 is 1.25

Think of it as the following

250 divided by 2 is 125 because 125+125=250

4 0

1 year ago

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Which dimensions can create only one unique triangle?

s2008m [1.1K]

Answer:

<h2>The dimensions must all add up to 180°.</h2>

Step-by-step explanation:

For example;

Your triangles' angles are: 56, 77, and 47.

56 + 77 + 47 = 180

*You did not give me any values to solve for, but just since you didn't- I'v provided an example to assist you in doing it yourself. If you want me to solve your full equation please add the angles or 3 dimensions of the triangle.

<h3><em>I hope this helped!</em></h3>

3 0

2 years ago

Find the equation to the line below!!!

elena55 [62]

6/2 is the answer rise over run method

7 0

3 years ago

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Complete the square to factor X^2 +10X=-8

ella [17]

Answer: $x=\sqrt{17}-5$ and $x = -\sqrt{17}-5$

Step-by-step explanation:

Alright, lets get started.

The given equation is :

$x^{2} +10x = -8$

Adding 8 in both sides, it will become

$x^{2} +10x + 8 = -8 +8$

$x^{2} +10x + 8 = 0$

To make it perfect square, we need to add 25 and subtract 25

$x^{2} +10x + 8 +25-25= 0$

$x^2+10x+25+8-25=0$

$(x+5)^2+8-25=0$

$(x+5)^2-17=0$

Adding 17 in both sides

$(x+5)^2=17$

taking square root

$x+5=\sqrt{17}$

So,

$x=\sqrt{17}-5$ and $x = -\sqrt{17}-5$ .. Answer

Hope it will help :)

7 0

2 years ago

Read 2 more answers

if a cylinder with height 9 inches and radius r is filled with water, it can fill a certain pitcher. how many of these pitchers

dalvyx [7]

Answer:

4 pitchers

Step-by-step explanation:

we know that

The volume of a cylinder is equal to

$V=\pi r^{2}h$

step 1

Find the volume of the cylinder with height 9 inches and radius r

substitute the given values

$V_1=\pi r^{2}(9)$

$V_1=9\pi r^{2}\ in^3$

step 2

Find the volume of the cylinder with height 9 inches and radius 2r

substitute the given values

$V_2=\pi (2r)^{2}(9)$

$V_2=36\pi r^{2}\ in^3$

step 3

we know that

The volume of the cylinder 1 can fill a certain pitcher,

The volume of the pitcher is the same that the volume of cylinder 1

therefore

the number of pitchers that can be filled by the second cylinder is equal to divide the volume of the second cylinder by the volume of the first cylinder

$\frac{36\pi r^{2}}{9\pi r^{2}}=4\ pitchers$

3 0

2 years ago