Answer:
a) For this case we define the random variable as X ="waiting time during peak hours" and we know that this distribution follows an uniform distribution:
Where a and b represent the limits of the distribution.
b) 
And the height for this case would be 0.125
Step-by-step explanation:
Part a
For this case we define the random variable as X ="waiting time during peak hours" and we know that this distribution follows an uniform distribution:
Where a and b represent the limits of the distribution.
Part b
For this case the density function would be given by:
And the height for this case would be 0.125
And 
for other case.
The cumulative distribution function would be given by:
Answer:
The integers are 11 and 12
Step-by-step explanation:
11 and 12 are consecutive positive integers, and 11 x 12 = 132.
Answer:
g(x)=-x-5
Step-by-step explanation:
Simplify parenthesis by distribution:
g(x)=-x-3+2-4
Addition and Subtraction:
-3+2=-1, -1-4=-5
Finalize since no more simplification:
g(x)=-x-5
Pls give thx and brainliest wanna level up
We are asked to solve for the width "x" in the given problem. To visualize the problem, see attached drawing.
We have the area of the swimming pool such as:
Area SP = l x w
Area SP = 10 * 16
Area SP = 160 feet2
Area of the swimming pool plus the sidewalk with uniform width:
Area SP + SW = (10 + x) * (16 + x)
160 + 155 = 160 + 10x + 16x + x2
160 -160 + 155 = 26x + x2
155 = 26 x + x2
x2 + 26x -155= 0
Solving for x, we need to use quadratic formula and the answer is 5 feet.
The value of x is
<span>
5 feet. </span>
Answer:
Step-by-step explanation:
a) if the population at the beginning of the year 2000 was 7500 people,
The 1-year percent change in the city's population would be
3.6/100 × 7500 = 270
b) The population after 1 year is
7500 - 270 = 7230
The percentage of the previous value of the population to its new value for each year is
7230/7500 × 100 = 96.4%
c) the 1-year growth factor for the population of the city would be
(1 - 0.036)^1 = 0.964
d) the function, g that determines the population of the city (in thousands of people) in terms of the number of years t since the beginning of 2000 would be
g = 7500(1 - 0.036)^t
g = 7500(0.964)^t
