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madreJ [45]
3 years ago
9

The difference between 33 1/3% and 33%

Mathematics
1 answer:
Luden [163]3 years ago
6 0

Answer:

_

1/3, or 0.3 is there difference

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(7,5), (r,9) m=6<br><br> What is r?
Igoryamba

Answer:

The answer is that r = 7/6

Step-by-step explanation:

Given point: (7, 5)

Given slope: m = 6

Use the point slope form of the equation:

y - y1 = m(x - x1)

y - 5 = 6(x - 7)

y - 5 = 6x - 7

y = 6x + 2

Now, find r for the point (r, 9) by substitution:

9 = 6x + 2

6x + 2 = 9

6x = 7

x = 7/6

Proof:

y = 6x + 2

f(x) = 6x + 2

f(7/6) = 6(7/6) + 2

= 42/6 + 2

= 7 + 2 = 9, giving (7/6, 9). r = 7/6

Hope this helps! Have a great day!

4 0
3 years ago
8^10 x 8^4 simplified write your answer as a power
boyakko [2]
Answer: 8^14

8^10 x 8^4= 8^14
6 0
3 years ago
Read 2 more answers
17. Four identical bags of cement and a
pogonyaev
The mass of each bag of cement is 16.5 kg. Check photo for steps and details, hope this helped! Please mark brainliest if you think this was helpful c:

5 0
3 years ago
Please help me with this. an explanation would be great as well
Ira Lisetskai [31]

Answer:

A

Step-by-step explanation:

test the constant 1/2 + (1/2)*(-3) = -2/2 = -1

6 0
2 years ago
Read 2 more answers
Cubed root x cubed root x2​
Yuki888 [10]

Answer:

Final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

Step-by-step explanation:

Given problem is \sqrt[3]{x}\cdot\sqrt[3]{x^2}.

Now we need to simplify this problem.

\sqrt[3]{x}\cdot\sqrt[3]{x^2}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}

Apply formula

\sqrt[n]{x^p}\cdot\sqrt[n]{x^q}=\sqrt[n]{x^{p+q}}

so we get:

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{1+2}}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{3}}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x

Hence final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

7 0
3 years ago
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