Answer:
The answer is that r = 7/6
Step-by-step explanation:
Given point: (7, 5)
Given slope: m = 6
Use the point slope form of the equation:
y - y1 = m(x - x1)
y - 5 = 6(x - 7)
y - 5 = 6x - 7
y = 6x + 2
Now, find r for the point (r, 9) by substitution:
9 = 6x + 2
6x + 2 = 9
6x = 7
x = 7/6
Proof:
y = 6x + 2
f(x) = 6x + 2
f(7/6) = 6(7/6) + 2
= 42/6 + 2
= 7 + 2 = 9, giving (7/6, 9). r = 7/6
Hope this helps! Have a great day!
Answer: 8^14
8^10 x 8^4= 8^14
The mass of each bag of cement is 16.5 kg. Check photo for steps and details, hope this helped! Please mark brainliest if you think this was helpful c:
Answer:
A
Step-by-step explanation:
test the constant 1/2 + (1/2)*(-3) = -2/2 = -1
Answer:
Final answer is
.
Step-by-step explanation:
Given problem is
.
Now we need to simplify this problem.
![\sqrt[3]{x}\cdot\sqrt[3]{x^2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D)
![\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E1%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D)
Apply formula
![\sqrt[n]{x^p}\cdot\sqrt[n]{x^q}=\sqrt[n]{x^{p+q}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Ep%7D%5Ccdot%5Csqrt%5Bn%5D%7Bx%5Eq%7D%3D%5Csqrt%5Bn%5D%7Bx%5E%7Bp%2Bq%7D%7D)
so we get:
![\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{1+2}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E1%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D%3D%5Csqrt%5B3%5D%7Bx%5E%7B1%2B2%7D%7D)
![\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E1%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D%3D%5Csqrt%5B3%5D%7Bx%5E%7B3%7D%7D)
![\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E1%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D%3Dx)
Hence final answer is
.