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Simora [160]
3 years ago
12

Factor the polynomial: 3x^2 - 9x - 30

Mathematics
2 answers:
svp [43]3 years ago
8 0
NICKI IS THE QUEEN OF RAPPP
soldi70 [24.7K]3 years ago
3 0
It would be 3(x-5)(x+2)
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Use the percent bar model to find the missing percent
Ne4ueva [31]

A percentage is a way to describe a part of a whole. The missing percent on the bar model is equal to 12.5%.

<h3>What are Percentages?</h3>

A percentage is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25 which is equal to 25%.

To convert a fraction to a percentage, convert the fraction to decimal form and then multiply by 100 with the '%' symbol.

On the percent bar model, above the missing percentage, the fraction is given as 1/8.

Now, the given fraction 1/8 in the form of percentage can be written as,

1/8

= 1/8 × 100%

= 0.125 × 100%

= 12.5%

Hence, the missing percent on the bar model is equal to 12.5%.

Learn more about Percentages here:

brainly.com/question/6972121

#SPJ1

3 0
2 years ago
First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x
e-lub [12.9K]

Answer:

(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

\int x ln(5+x)dx

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

\int (U-5) ln(U)dU

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

\int (pq')=pq-\int qp'

so we must define p, q, p' and q':

p=ln U

p'=\frac{1}{U}dU

q=\frac{U^{2}}{2}-5U

q'=U-5

and now we plug these into the formula:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU

Which simplifies to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU

Which solves to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C

so we can substitute U back, so we get:

\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C

and now we can simplify:

\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

notice how all the constants were combined into one big constant C.

7 0
3 years ago
2 Points
Mashcka [7]

Answer:

C

Step-by-step explanation:

Factor: -7x^2 -5x+18

Factor -1 out of 7x^2 -5x +18:

−(7x^2+5x−18)

Factor.

1. 18 is negative, so a negative number multiplied by a postive number.

2. You can't factor 7, so 7x times x.

(7x−9)(x+2)

4 0
4 years ago
Before you make an offer on a home, you should first make sure your mortgage loan application has received a
Nadya [2.5K]
After you submit your loan application, the lender does an extensive check on your finances and credit record. If everything checks out, the lender will state the exact amount they're willing to loan you. The preapproval is good for a set amount of time, usually 60–90 days.
6 0
3 years ago
YOU CAN CHANGE SUBTRACTION TO ADDITION, BUT YOU DON'T CHANGE ADDITION TO SUBTRACTION WHEN CALCULATING INTEGERS?
olya-2409 [2.1K]

Step-by-step explanation:

<h2>a - b = a + (-b)</h2><h2>a + b = a - (-b)</h2>

for any real numbers

5 0
3 years ago
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