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Valentin [98]
3 years ago
15

O really need help can you please help me

Mathematics
1 answer:
rusak2 [61]3 years ago
8 0

Answer:

yes

Step-by-step explanation:

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What is the slope of the line passing through the points (2, 5) and (-1, -4)? show your work
Sati [7]

Answer:

We can solve this question using the slope equation which is y2-y1/x2-x1

If you use that formula and sub in the coordinates

-4 - 5 / -1-2

-9/-3

= 3

The slope should be 3/1

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3 years ago
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NEED ANSWER ASAP!!
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Answer:

A=-2; B=-1

Step-by-step explanation:

3a - 2b + 4 =0

2a -5b -1 = 0

Let's multiple the top equation by 2, and the bottom by -3, and then use addition.

[3a - 2b + 4 =0]*2

[2a -5b -1 = 0]*(-3)

6a-4b+8=0

-6a+15b+3=0

Now add the two equations together:

11b + 11 = 0

Subtract 11 from both sides

11b = -11

Divide both sides by 11

b=-1

Substitute in the first equation:

3a - 2(-1) + 4 = 0

Simplify to get 3a+6 = 0

Subtract 6 from both sides to get 3a = -6

Divide both sides by 3 to get a=-2

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2 years ago
The ratio of the sides of a triangle is 7:11:15. If the
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I don’t understand this help please
Elodia [21]

Answer:

  9

Step-by-step explanation:

The first simplification we can make is to replace 6^0 with 1.

The first rules of exponents we can apply are ...

  <em>(a·b)^c = a^c·b^c</em> . . . . . . similar to the distributive property

<em>   (a^b)^c = a^(b·c)</em>

This reduces your expression to ...

  (2^8\cdot 3^{-5})^{-2}\cdot\left(\dfrac{3^{-2}}{2^3}\right)^4\cdot 2^{28}=2^{8(-2)}\cdot 3^{-5(-2)}\cdot\dfrac{3^{-2(4)}}{2^{3(4)}}\cdot 2^{28}\\\\=2^{-16}\cdot 3^{10}\cdot\dfrac{3^{-8}}{2^{12}}\cdot 2^{28}

Now we can apply another two rules of exponents:

<em>   (a^b)(a^c) = a^(b+c)</em>

<em>   1/a^b = a^-b</em>

Using these, we have ...

  =2^{-16-12+28}\cdot 3^{10-8}\\\\=2^0\cdot 3^2\\\\=1\cdot 9=9

The value of the expression is 9.

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