Question

Jackson is building a small rectangular basketball section in his backyard. The length of the section will be 1.25 times the width of the section. Part A (2 POINTS) Create an equation to represent the area of the basketball section, A, in terms of the width, w. Part B (5 POINTS) Jackson decides to make the area of the basketball section 245 square feet. What are the dimensions, in feet, of the basketball section?

Answer 1

Answer:

Part A) $A=1.25W^2$

Part B) Length: 17.5 feet and Width: 14 feet

Step-by-step explanation:

Part A) Create an equation to represent the area of the basketball section A, in terms of the width W.

Let

L ----> the length of the  rectangular basketball section

W ---> the width of the  rectangular basketball section

we know that

The area of the rectangular basketball section is equal to

$A=LW$ ----> equation A

The length of the section will be 1.25 times the width of the section

so

$L=1.25W$ ----> equation B

substitute equation B in equation A

$A=(1.25W)W$

$A=1.25W^2$

Part B) Jackson decides to make the area of the basketball section 245 square feet. What are the dimensions, in feet, of the basketball section?

we have

$A=1.25W^2$

$A=245\ ft^2$

so

$245=1.25W^2$

solve for W

$W^2=245/1.25\\W^2=196\\W=14\ ft$

Find the value of L

substitute the value of W in the equation B

$L=1.25(14)=17.5\ ft$

therefore

The dimensions are :

Length: 17.5 feet

Width: 14 feet