1) his time would have to be less than 11.54
2)each member would have to run a time of about 11.91
3) Assuming that Dwane ran a time of 11.53 the average amount of time it took each member to run the 100 meters will be about 12.2 seconds per 100 meters
Answer:
1
Step-by-step explanation:
One is the smallest multiple of 50. We can find this by finding all the multiples of 50. The multiples of 50 are: 1, 2, 5, 10, 25, and 50.
We can see that one is the smallest multiple because it is less than 2, 5, 10, 25 and 50. So, that means the answer to the question is 1.
Hope this helps.
Hello from MrBillDoesMath!
Answer:
The first marker is labeled 208708; the second (consecutive) one 208709
Discussion:
Call the first mile marker "m". Then
m + (m+1) = 417417 => combine like terms
2m + 1 = 417417 => subtract 1 from both sides
2m = 417416 => divide both sides by 2
m = 417416/2 = 208708
Note: m and (m+1) are consecutive as they immediately follow each other in the set of integers.
Thank you,
MrB
Answer:
In 3 - 5:
3 + (-5), and -5 + 3
In 5 - 3:
5 + (-3), and -3 + 5
Step-by-step explanation:
Category : 3 - 5
Values must equal -2
3 + (-5) = 3 - 5 = -2
-5 + 3 = -2
Category : 5 - 3
Values must equal 2
5 + (-3) = 5 - 3 = 2
-3 + 5 = 2
If my answer is incorrect, pls correct me!
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-Chetan K
3t = 5(3-t)
3t = 15 - 5t
3t + 5t = 15
8t = 15
t = 15/8
t = 1 7/8
7/8 * 60 mins = 52.50 minutes
t = 1 hour and 52.5 minutes
It took Stu 1 hour and 52.5 minutes to hike the trail one way.
