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2 years ago

Which value is equivalent to

Mathematics

1 answer:

Ksenya-84 [330]2 years ago

6 0

Answer:

$\frac{25}{144}$

Step-by-step explanation:

$(\frac{7 * 5 * 2}{7 * 3} )^2 * (\frac{5^0}{2^-3})^3 * 2^{-9}$

Simplified becomes;

$(\frac{10}{3})^2 * 2^3 * \frac{1}{2^9}$

Simplifying further gives; $\frac{25}{144}$

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Please solve the question and chose from the provided answer options.

Nezavi [6.7K]

Answer:

Option A is correct.

Step-by-step explanation:

We are given the expression:

w(x) = (x+125)^1/3

We need to find w(50)

Putting x = 50 in the above equation

w(x) = (x+125)^1/3

w(50) = (50+125)^1/3

w(50) = (175)61/3

w(50) = 5.59

w(50) = 5.6

So, Option A is correct

7 0

3 years ago

What theorem shows that GTY=GUX?

wlad13 [49]

Answer:SAS

Step-by-step explanation:

The line show congruent line which means two sides. Since it has vertical angles it has a angle.

6 0

3 years ago

What are the common factors of 35 and 60?

Ksivusya [100]

I think it is 5 !!!!!!!!!!!!!!

3 0

3 years ago

In the diagram, parallel lines P and Q are cut by transversal R.

Paraphin [41]

Answer:

x=125

Step-by-step explanation:

7 0

2 years ago

A rocket is launched at 85 ft./s from a launch pad that’s 28 feet above the ground. which equation can be used to determine the

3241004551 [841]

Answer:

$h(t)=-16t^2+85t+28$ is equation of height of rocket.

Option D is correct.

Step-by-step explanation:

Given: A rocket is launched with speed 85 ft/s from a height 28 feet.

Launching a rocket follows the path of parabola. The equation of rocket should be parabolic.

Parabolic equation of rocket is

Formula: $h(t)=\dfrac{1}2gt^2+v_0t+h_0$

g ⇒ acceleration due to gravity (-32 ft/s)

v ⇒ Initial velocity ( $v_0=85\ ft/s$ )

h ⇒ Initial height ( $h_0=28\ feet$ )

h(t) ⇒ function of height at any time t

Substitute the given values into formula

$h(t)=\frac{1}{2}(-32)t^2+(85)t+28$

$h(t)=-16t^2+85t+28$

D is correct.

6 0

3 years ago

Read 2 more answers