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saw5 [17]
3 years ago
5

There are 199 green marbles and 199 red marbles in a bag. How many marbles must be chosen to be certain we have the following. F

our red or three green?
Mathematics
2 answers:
Leya [2.2K]3 years ago
8 0

Answer:

203 for four red and 202 for three green.

Step-by-step explanation:

Consider the worst possible choice. If you want four red then imagine the worst possible case. That'd be picking all 199 marbles before any red, and after you pick all 199 green marbles you still need four red, and 199+4=203. For green, do the same thing and you get 199+3=202

tankabanditka [31]3 years ago
7 0

There are 203 for four red and 202 for three green.

Given that,

  • There are 199 green marbles and 199 red marbles in a bag.

Based on the above information, the calculation is as follows:

Since there is 4 red or three green.

So,

We can solve like

= 199 + 3

= 202

And,

= 199 + 4

= 203

Therefore we can conclude that there are 203 for four red and 202 for three green.

Learn more: brainly.com/question/16115373

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What is the base of a triangle with an area of 207 square inches and a height of 18 inches ?
xenn [34]

Answer:

A=1/2 B x H

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2 years ago
Situation B: Suppose that 40% of Missourians favor increasing the minimum wage. Twelve Missourians are selected at random and as
yulyashka [42]

Answer:

14.19% probability that exactly three of the twelve support the increase.

Step-by-step explanation:

For each Missourian, there are only two possible outcomes. Either they support the increase, or they do not. The probability of a Missourian supporting the increase is independent of other Missourians. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

40% of Missourians favor increasing the minimum wage.

This means that p = 0.4

Twelve Missourians are selected at random and asked whether they support the increase.

This means that n = 12

Find the probability that exactly three of the twelve support the increase.

This is P(X = 3).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{12,3}.(0.4)^{3}.(0.6)^{9} = 0.1419

14.19% probability that exactly three of the twelve support the increase.

7 0
3 years ago
Santa's elves are selling
Andreas93 [3]

cost of one peppermint cookies = $ 0.6

cost of one cinnamon sugar cookies = $ 0.3

<h3><u>Solution:</u></h3>

Let "p" be the cost of one peppermint cookies

Let "c" be the cost of one cinnamon sugar cookies

<u><em>To find: cost of each cookie</em></u>

<h3><u><em>On  the first day, they sold 120  peppermint cookies and 30  cinnamon sugar cookies for a  total of $81</em></u></h3>

We can frame a equation as:

120  peppermint cookies x cost of one peppermint cookies + 30  cinnamon sugar cookies x cost of one cinnamon sugar cookies = $ 81

120 \times p + 30 \times c = 81

120p + 30c = 81  --------- eqn 1

<h3><u><em>The next day  they made $60 by selling 70  peppermint cookies and 60  cinnamon sugar cookies</em></u></h3>

70  peppermint cookies x cost of one peppermint cookies + 60  cinnamon sugar cookies x cost of one cinnamon sugar cookies = $ 60

70 \times p + 60 \times c = 60

70p + 60c = 60 --------- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "p" and "c"

Multiply eqn 1 by 2

240p + 60c = 162  --- eqn 3

Subtract eqn 2 from eqn 3

240p + 60c = 162

70p + 60c = 60

(-) -------------------------

170p = 102

<h3>p = 0.6</h3>

Substitute p = 0.6 in eqn 1

120p + 30c = 81

120(0.6) + 30c = 81

72 + 30c = 81

30c = 9

<h3>c = 0.3</h3>

<u><em>Summarizing the results:</em></u>

<em>cost of one peppermint cookies = $ 0.6</em>

<em>cost of one cinnamon sugar cookies = $ 0.3</em>

6 0
3 years ago
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