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Alenkasestr [34]
4 years ago
15

Can a rectangle also be a rhombus? Explain.

Mathematics
2 answers:
Sophie [7]4 years ago
5 0
No. A rectangle MUST have 2 pairs of parallel sides and all equal angles. 
A rhombus has 2 pairs or parallel sides with 2 pairs of equal angles.
motikmotik4 years ago
4 0
<u><em>Answer:</em></u>
No

<u><em>Explanation:</em></u>
<u>There are some significant differences between the rectangle and the rhombus including:</u>
<u>A rectangle:</u>
1- each two opposite sides are equal
2- all angles are right angles

<u>A rhombus:</u>
1- all sides are equal
2- each two opposite angles are equal but not right

Based on the above differences, we can conclude that a shape can never be a rectangle and a rhombus at the same time

Hope this helps :)


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?? “solve the missing elements for each problem. use 3.14 for area
velikii [3]

Answer:

Problem 4:

Radius = 11 cm.

Circumference = 69.08 cm.

Problem 5:

Radius = 14 mm.

Circumference = 87.92 mm.

Problem 6:

Radius = 9 inches.

Circumference = 56.52 inches.

Problem 7:

Diameter = 32 ft.

Circumference = 100.48 ft.

Problem 8:

Diameter = 26 yards.

Circumference = 81.64 yards.

Problem 9:

Diameter = 12 cm.

Circumference = 37.68 cm.

Step-by-step explanation:

Problem 4:

Given:

Diameter GH = 22 cm

We need to find the radius EF and Circumference of the circle.

Now radius is given by half of the diameter

Also Circumference is given by π times diameter.

Radius EF = \frac{1}{2}\times Diameter = \frac{1}{2}\times 22 = 11 \ cm

Circumference = \pi \times Diameter = 3.14 \times 22 = 69.08\ cm

Hence Radius = 11 cm

Circumference = 69.08 cm.

Problem 5:

Given:

Diameter OP = 28 mm

We need to find the radius MN and Circumference of the circle.

Now radius is given by half of the diameter

Also Circumference is given by π times diameter.

Radius MN = \frac{1}{2}\times Diameter = \frac{1}{2}\times 28 = 14 \ mm

Circumference = \pi \times Diameter = 3.14 \times 28 = 87.92\ mm

Hence Radius = 14 mm

Circumference = 87.92 mm.

Problem 6:

Given:

Diameter EF = 18 inches

We need to find the radius CD and Circumference of the circle.

Now radius is given by half of the diameter

Also Circumference is given by π times diameter.

Radius CD = \frac{1}{2}\times Diameter = \frac{1}{2}\times 18 = 9 \ in

Circumference = \pi \times Diameter = 3.14 \times 18 = 56.52\ in

Hence Radius = 9 inches.

Circumference = 56.52 inches.

Problem 7:

Given:

Radius GH = 16 ft

We need to find the Diameter CD and Circumference of the circle.

Now Diameter is given by twice the radius.

Also Circumference is given by π times diameter.

Diameter KJ = 2 \times radius = 2 \times 16 = 32 \ ft

Circumference = \pi \times Diameter = 3.14 \times 32 = 100.48\ ft

Hence Diameter = 32 ft.

Circumference = 100.48 ft.

Problem 8:

Given:

Radius LM = 13 yards

We need to find the Diameter CD and Circumference of the circle.

Now Diameter is given by twice the radius.

Also Circumference is given by π times diameter.

Diameter NO = 2 \times radius = 2 \times 13 = 26 \ yards

Circumference = \pi \times Diameter = 3.14 \times 26 = 81.64\ yards

Hence Diameter = 26 yards.

Circumference = 81.64 yards.

Problem 9:

Given:

Radius NO = 6 cm

We need to find the Diameter CD and Circumference of the circle.

Now Diameter is given by twice the radius.

Also Circumference is given by π times diameter.

Diameter PQ = 2 \times radius = 2 \times 6 = 12 \ cm

Circumference = \pi \times Diameter = 3.14 \times 12 = 37.68\ cm

Hence Diameter = 12 cm.

Circumference = 37.68 cm.

3 0
3 years ago
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Diano4ka-milaya [45]

Answer:

V = 125.6 in³

Step-by-step explanation:

let V be volume, h the height and r the radius, then the equation relating the quantities is

V = khr² ← k is the constant of variation

To find k use the condition V = 402.12, h = 8, r = 4

402.12 = k × 8 × 4² = 128k ( divide both sides by 128 )

3.14 = k [ note 3.14 is π )

V = 3.14hr² ← equation of variation [ V = πr²h ]

Given r = 2 and h = 10, then

V = 3.14 × 10 × 2² = 3.14 × 40 = 125.6

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3 years ago
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hram777 [196]

Answer:

D. 15cm2

Step-by-step explanation:

To find the area of a triangle, you multiply the base (10cm) and height of the triangle (3cm) and divide that by 2. So 10×3=30. Then, you need to divide this by 2. Since 30 is an even number, you won't get a decimal. So 30/2=15. And dont forget your units!

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Ronch [10]

Answer:

9 and 6/23

Step-by-step explanation:

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3 0
3 years ago
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Find the length of the altitude drawn to the hypotenuse. The triangle is not drawn to scale.
Serga [27]
We can solve this by understanding triangle rules and seeing the two right triangles that together form the whole right triangle. Lastly we'll use some basic Trig.
Let's start by labeling the triangles:
Let's make the bottom left angle (next to 5) "b"
Then we'll call the small angle at the top, which is the apex of the small triangle, "a". The height of the triangles we'll call "x".
So for the angles at this point, if a + b (as we've called them) are the other 2 angles of a right triangle, then a + b = 90.
Why? because all (3) angles of any triangle always sum (add up) to the 180.
if a + b = 90, then a = 90-b
Now let's look at the triangle on the right: it has 90 as it's left angle, and b as apex (top) angle, the angle on the right must add to b to make 90, so it's 90-b
plug "a" in for "90-b" --> now we have an a, b, and 90 for the small right and for the small left triangle.
For the left triangle: take the tangent (tan) of angle a, which = the opposite side (O) ÷ adjacent side (A) --> tan(a) = O/A = 5/x
For the other triangle: tangent of that angle a = O/A --> tan(a) =x/26
Now if tan(a) = 5/x AND tan(a) = x/26, we can plug one into the other:
tan(a) = x/26
5/x = x/26
cross-multiply
x * x = 5 * 26
{x}^{2}  = 130 \\  \sqrt{ {x}^{2} }  =  \sqrt{130}  \\ x =  \sqrt{130}
5 0
3 years ago
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