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Kamila [148]
2 years ago
13

Find the volume of this the sphere round to the nearest tenth 7in [?]in*3

Mathematics
1 answer:
Lyrx [107]2 years ago
5 0

Answer:

1436.8

Step-by-step explanation:

4/3×π×7³

= 1372π/3

≈ 1436.8

Answered by GAUTHMATH

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4. After taking 20% off the original price, Amber paid $35 for her dress. What was the original price? A. $63.75 B. $54.25 O C.
larisa [96]

Answer: D. $43.75

Step-by-step explanation:

3 0
3 years ago
9. Mark is filling up crates with watermelons for the food drive. He has large watermelons that weigh 10 pounds each and smaller
abruzzese [7]
9. 10x + 5y is the equation for larger watermelons + smaller watermelons (you did not provide information about the medium watermelons, so we must assume given the options you miswrote one of them). We can hold NO MORE than 500 pounds, so 10x + 5y must be smaller than 500. The best answer is C assuming that "5y" represents your "Medium Watermelons"- because smaller watermelons are stated to be 5 and medium ones should therefore be between 5 and 10, the option provided by A wouldn't make since because 3 pounded watermelons are not "medium" in comparison to the "small ones" that are heavier/bigger. Your best option is C, 10x + 5y < 500, the exact answer technically would be 10x + 5y <= 500.
4 0
3 years ago
2(a³+b²+11)+1(3+a³+b+11)
Ann [662]

Answer:

2(a^3+b^2+11)+1(3+a^3+b+11)=3a^3+2b^2+b+36

Step-by-step explanation:

I assume that you need simplification of the given expression.

The given expression is:

2(a^3+b^2+11)+1(3+a^3+b+11)

Using distributive property and multiplying 2 inside the parenthesis and 1 inside the other parenthesis. This gives,

2(a^3+b^2+11)=2\times a^3+2\times b^2+2\times 11\\2(a^3+b^2+11)=2a^3+2b^2+22\\\\1(3+a^3+b+11)=1\times 3+1\times a^3+1\times b+1\times 11\\1(3+a^3+b+11)=3+a^3+b+11=a^3+b+14

Therefore, 2(a^3+b^2+11)+1(3+a^3+b+11) is equal to:

2a^3+2b^2+22+a^3+b+14

Now, combining like terms using the commutative property of addition, we get:

=(2a^3+a^3)+2b^2+b+(22+14)\\=3a^3+2b^2+b+36

Therefore, the simplified form is 3a^3+2b^2+b+36

8 0
3 years ago
Simplify. Use a horizontal format. <br><br> (-2y2 - 4y - 11) + (4y2 - 4y)
dimulka [17.4K]
-4y-11 that the answer hope it helps
6 0
3 years ago
Please Help Me ASAP Will Thank Rate 5 Starts And Mark Brainliest If You Are CORRECT
Ivan

Answer:

The correct option is 4.

Step-by-step explanation:

It is given that figure ABCD is transformed to figure A′B′C′D′.

The vertices of ABCD are A(1,1), B(3,3), C(4,2) and D(4,1).

The vertices of A'B'C'D' are A'(1,-3), B'(3,-1), C'(4,-2) and D'(4,-3).

It is clear that the figure translate 4 units down and the rule of translation is

Translation is a rigid transformation, it means image and preimge are congruent.

Since ABCD is translate 4 units down to make A′B′C′D′, therefore

Congruent part of congruent figures are congruent.

                 

Therefore the correct option is 4.

I Hope It's Helpful :)

4 0
3 years ago
Read 2 more answers
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