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Leokris [45]
3 years ago
11

Identify the first five terms of the sequence in which a1 = 5 and an = 2an−1−3 for n ≥ 2.

Mathematics
1 answer:
ziro4ka [17]3 years ago
3 0

Answer:

5, 7, 11, 19, 35

Step-by-step explanation:

Using the recursive formula and a₁ = 5 , then

a₂ = 2a₁ - 3 = (2 × 5) - 3 = 10 - 3 = 7

a₃ = 2a₂ - 3 = (2 × 7) - 3 = 14 - 3 = 11

a₄ = 2a₃ - 3 = (2 × 11) - 3 = 22 - 3 = 19

a₅ = 2a₄ - 3 = (2 × 19) - 3 = 38 - 3 = 35

Thus the first 5 terms are

5, 7, 11, 19, 35

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Answer:

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5 0
3 years ago
Write 85% as an frotion in simpfulest form
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7 0
2 years ago
If f(x)=x/2-2 and g(x)=2x^2+x-3, find (f+g)(x)
Lelu [443]
Hello : 
<span>If f(x)=x/2-2 and g(x)=2x^2+x-3, find (f+g)(x)
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4 0
4 years ago
Read 2 more answers
If p(x)=x^3-3x^2-x+3 and p(3)=0, what is a factor of p(x)
IRISSAK [1]
<h3>Answer:   x-3</h3>

Since p(3) = 0, this means x = 3 plugs into p(x) to get 0

We can write p(x) as p(x) = (x-3)q(x) where q(x) is some other polynomial that multiplies with (x-3) to lead to x^3-3x^2-x+3

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No matter what the result of q(3) was, it doesn't matter because it multiplies with 0 to get 0.

The general rule is: if p(k) = 0, then x-k is a factor of p(x). This is a special case of the remainder theorem.

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3 years ago
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see attachment for graph


7 0
4 years ago
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