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Reptile [31]
3 years ago
9

It is widely reported that high school students spend an average of 7 hours per week working on homework. Miss Bonnar, a high sc

hool English teacher, questions this report. She believes the students at her high school spend more than 7 hours per week working on homework. She surveys a random sample of 95 students and plans to use the resulting data to conduct a hypothesis test. Suppose the p-value from this hypothesis test is 0.01. Which of the following is a correct interpretation of this p-value?
A. Approximately 1% of the students in the sample spend more than 7 hours per week working on homework.
B. The probability of obtaining a result at least as extreme as the one observed, if the null hypothesis is true, is 0.01.
C. The probability that the null hypothesis is true is 0.01.
D. The probability that the null hypothesis is false is 0.01.
E. If we assume to begin with that the null hypothesis is false, there is only a 1% chance we will reject that null hypothesis.
Mathematics
1 answer:
yulyashka [42]3 years ago
8 0

Answer:

B. The probability of obtaining a result at least as extreme as the one observed, if the null hypothesis is true, is 0.01.

Step-by-step explanation:

The answer choice B is in fact the definition of p-value.

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Zina [86]

Answer:

Median = 27.5 Mean = 28.25

Step-by-step explanation:

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3 years ago
Can you give me the answers to the picture i showed u
valina [46]

Answer:

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Step-by-step explanation:

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3 years ago
Read 2 more answers
A laptop producing company also produces laptop batteries, and claims that the batteries
gregori [183]

Answer:

There is enough evidence to support the claim that the batteries power the laptops for significantly less than 4 hours. (P-value = 0).

The null and alternative hypothesis are:

H_0: \mu=4\\\\H_a:\mu< 4

Step-by-step explanation:

<em>The question is incomplete: To test this claim a sample or population standard deviation is needed.</em>

<em>We will estimate that the sample standard deviation is 2 hours, and use a t-test to test that claim.</em>

<em> NOTE (after solving): The difference between the sample mean and the mean of the null hypothesis is big enough to reject the null hypothesis, even when we have a sample standard deviation of 3.5 hours, which can be considered bigger than the maximum standard deviation for the sample.</em>

This is a hypothesis test for the population mean.

The claim is that the batteries power the laptops for significantly less than 4 hours.

Then, the null and alternative hypothesis are:

H_0: \mu=4\\\\H_a:\mu< 4

The significance level is 0.05.

The sample has a size n=500.

The sample mean is M=3.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=2.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{2}{\sqrt{500}}=0.0894

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{3.5-4}{0.0894}=\dfrac{-0.5}{0.0894}=-5.5902

The degrees of freedom for this sample size are:

df=n-1=500-1=499

This test is a left-tailed test, with 499 degrees of freedom and t=-5.5902, so the P-value for this test is calculated as (using a t-table):

P-value=P(t

As the P-value (0) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the batteries power the laptops for significantly less than 4 hours.

5 0
3 years ago
What is the area of the kite?
enot [183]

The area of the kite is 2.25 square feet

<h3>How to determine the area of the kite?</h3>

The area of the kite is calculated using:

Area = 0.5 * pq

Where p and q are the diagonals of the kite.

In this figure,

p = 3

q = 0.75 * 2 = 1.5

So, we have:

Area = 0.5 * 3 * 1.5

Evaluate

Area = 2.25

Hence, the area of the kite is 2.25

Read more about areas at:

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4 0
1 year ago
$6x + $15 ≤ $70<br><br><br> I have no idea- xd
Delvig [45]

Answer:

x = 9

Step-by-step explanation:

6 × 9 = 54

54 + 15 = 69, which is less than 70.

3 0
2 years ago
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