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adelina 88 [10]
2 years ago
15

How many ways can 4 student ma be chosen from a class of 30 students is ?

Mathematics
2 answers:
snow_tiger [21]2 years ago
6 0
If the order doesn't matter then you have to apply the combination formula:

³⁰C₄ = (30!)/(4!)(30-4)! = 27,405 WAYS

andre [41]2 years ago
3 0
That's we can solve by using a combination algorithm: C^4_{30}=\frac{30*29*28*27}{4*3*2*1} = 27405
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What is the solution of x+8/5x-1>0?
DerKrebs [107]

Answer:

x<-8 or x>1/5

Step-by-step explanation:

\frac{x+8}{5x-1} >0

First we replace > symbol by = sign

\frac{x+8}{5x-1} =0

To solve for x we multiply 5x-1 on both sides

x+8 =0

x=-8

5x-1=0 solve for x

x= 1/5

WE got two values x=-8  and x= 1/5

Now we make a number line and check with each interval

x<-8,  -8<x<1/5,  x>1/5

Pick x= -9 and check with the given inequality

\frac{-9+8}{5(-9)-1} >0

1/46 >0 is true, so x<-8 satisfies our inequality

Pick x= 0 and check with the given inequality

\frac{0+8}{5(0)-1} >0

-8 >0 is false , -8<x<1/5 does not satifies our inequality

Pick x= 2 and check with the given inequality

\frac{2+8}{5(2)-1} >0

10/9>0 is true , x>1/5  satisfies our inequality

3 0
3 years ago
Read 2 more answers
Help me to answer this question pl​s
attashe74 [19]

Problem 1

Draw a straight line and plot P anywhere on it. Use the compass to trace out a faint circle of radius 8 cm with center P. This circle crosses the previous line at point Q.

Repeat these steps to set up another circle centered at Q and keep the radius the same. The two circles cross at two locations. Let's mark one of those locations point X. From here, we could connect points X, P, Q to form an equilateral triangle. However, we only want the 60 degree angle from it.

With P as the center, draw another circle with radius 7.5 cm. This circle will cross the ray PX at location R.

Refer to the diagram below.

=====================================================

Problem 2

I'm not sure why your teacher wants you to use a compass and straightedge to construct an 80 degree angle. Such a task is not possible. The proof is lengthy but look up the term "constructible angles" and you'll find that only angles of the form 3n are possible to make with compass/straight edge.

In other words, you can only do multiples of 3. Unfortunately 80 is not a multiple of 3. I used GeoGebra to create the image below, as well as problem 1.

8 0
2 years ago
I need this answer ASAP please! The rectangle in the figure is composed of six squares. Find the side length of the largest squa
Sladkaya [172]

Answer:

7

Step-by-step explanation:

the side length of the largest square is x

2x-1=3x-8

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3 0
3 years ago
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IN CASE YOU WROTE THE QUESTION WRONG AND MR JONES CHARGES $80 PER LESSON

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2 years ago
How can you tell that the data in the table is function or not?
stealth61 [152]

that is not a function, because there are two outputs for three. two inputs can have one output, but one input cant have two outputs.

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3 years ago
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