Answer:
<h2>Hyy There !! </h2>
Step-by-step explanation:
<h3><u>Question Says :- </u></h3>
• The Area of a sector when r = 9/2 and
θ = 5pi/6 radians ? .
? pi / ?
<h3><u>Circular Area of a Sector</u></h3>
Problems involving area of a sector can be solved easily. One should just obtain two essential information from the circle of interest, the central angle measure θ and radius r For angle measures in radians, the area A is calculated as :-
<h3>A = 1/2r^2θ. </h3>
<h3>Hope this helps you !! </h3>
Answer:
42w^2-20w^2+16
Step-by-step explanation:
Answer:
Step-by-step explanation:
14 Decigrams = 0.014 Hectograms
1) slope is 6 and y-intercept is ( 0,5) y = mx + b, m = 6, b = 5 y = 6x + 5 2)line passes through the points ( 3,6) and ( 6,3 ) First find the slope: m = (3-6)/(6-3) = -3/3 = -1 y = -x + b Plug in one of the given points (x,y) and find b 6 = -3 + b 9 = b <span> y = -x + 9</span> a horizontal line that passes through the point ( -1,7)Horizontal lines have a constant y-value and formaty = c where c is a constant number. y = 7 y=-3x+3x intercept: set y = 0 and solve for x0 = -3x + 33x = 3x = 1x-intercept: (1, 0) y-intercept: set x = 0 and solve for yy = -3(0) + 3y = 3y-intercept: (0,3) y=0,5x-1Is this two equations? The line y=0 has y-intercept at (0,0)The x-intercept is the entire x-axis y=5x-1x -intercept: Set y = 0 and solve for x y-intercept: Set x = 0 and solve for y
