Answer:
<h2>
RS = 47</h2>
Step-by-step explanation:
RV=VU and SW=WT ⇒ 
Therefore:

3x + 5 = 4x - 11 {subtract 5 from both sides)
3x = 4x - 16 {subtract 4x from both sides)
-x = -16 {divide both sides by (-1)}
x=16
So:
RS = 2x + 15 = 2×16 + 15 = 32 + 15 = 47
Answer:
Mean: 


Step-by-step explanation:
Given
See attachment for data
Solving (a): The mean
Mean is calculated as:

From the attached:

So, the mean is:



Solving (b): The median
; this is an even number. So, the median is:




This implies that the median is the average of the 7th and 8th item.
Next, is to order the data (in ascending order): <em>36.45, 38.03, 38.19, 39.17, 39.44, 40.1, 40.2, 40.2, 40.3, 43.1, 43.2, 43.4, 43.4, 43.4.</em>
The 7th and 8th items are: 40.2 and 40.2
The median is:



Solving (c): The mode
43.4 has the highest number of occurrence.
So:
