Answer:
68.8 sq. inches.
Step-by-step explanation:
The triangular surfaces have sides 2 in by 3 in by 4 in.
So, half perimeter, s = 
So, the area of the triangular face is
sq. inches.
Now, the total surface area of the right triangular prism will be (2.9 × 2) + 7(2 + 3 + 4) = 68.8 sq. inches. (Answer)
D because it the answer for your question because it
Answer:
Area Of a Right Angled∆
=><em><u> </u></em><em><u>1</u></em><em><u>/</u></em><em><u>2</u></em><em><u> </u></em><em><u>x </u></em><em><u>Base </u></em><em><u>x </u></em><em><u>Height</u></em>
Area of a ∆ Using Heron's Formula
=>

Where
- S = Semiperimeter
- a ,b& c = sides of the ∆
To put in into y=mx+b format, you have to subtract the x on both sides.
y=-x-5
This would be the answer.