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trasher [3.6K]
3 years ago
8

In Deductive reasoning you start from A __set of rules and conditions to determine what must be true? A. Unknown B.hypothetical

C. Induced D. Given
Mathematics
1 answer:
Maurinko [17]3 years ago
8 0

Answer:

Option D is correct.

In Deductive reasoning you start from a 'Given' set of rules and conditions to determine what must be true.

Step-by-step explanation:

Deductive reasoning is a top-to-down reasoning method that makes its conclusion on the basis of given premise(s) which is/are commonly assumed to be true.

It uses given rules, theorems, conditions, methods etc. to prove that other statements are true or not.

Hence, in Deductive reasoning you start from a 'Given' set of rules and conditions to determine what must be true.

Hope this Helps!!!

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Which graph represents a linear function? (4 points)
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Answer:

On the surface, it seems easy. Can you think of the integers for x, y, and z so that x³+y³+z³=8? Sure. One answer is x = 1, y = -1, and z = 2. But what about the integers for x, y, and z so that x³+y³+z³=42?

That turned out to be much harder—as in, no one was able to solve for those integers for 65 years until a supercomputer finally came up with the solution to 42. (For the record: x = -80538738812075974, y = 80435758145817515, and z = 12602123297335631. Obviously.)

Step-by-step explanation:

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What is the slope and y-intercept of this line?y -6x 2
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-48=-8x+8 solve the equation
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8 0
4 years ago
Read 2 more answers
The density of a American white oak tree is 752 kilograms per cubic meter. If the trunk of an American white oak tree has a circ
LuckyWell [14K]

Check the picture below.

\bf \textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\ \cline{1-1} C=4.5 \end{cases}\implies 4.5=2\pi r\implies \cfrac{4.5}{2\pi }=r \\\\[-0.35em] ~\dotfill

\bf \textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\ \cline{1-1} h=8\\ r=\frac{4.5}{2\pi } \end{cases}\implies V=\pi \left( \cfrac{4.5}{2\pi } \right)^2(8)\implies V=\begin{matrix} \pi \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix} \cdot \cfrac{20.25}{\begin{matrix} 4 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}\underset{\pi }{\begin{matrix} \pi^2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix} }}(\stackrel{2}{\begin{matrix} 8 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}})

\bf V=\cfrac{40.5}{\pi }~cm^3~\hspace{9em} \stackrel{\textit{since density is }752kg~per~cm^3}{density\implies 752\left( \cfrac{40.5}{\pi } \right)}\qquad \approx ~~9694

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3 years ago
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