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3 years ago

What is 9.286 as a mixed number

2 answers:

8 0

9.286

[To change to mixed number, count the number of digits after the decimal point. There are 3 digits, so the denominator will be 1000]

$9.286 = 9 \frac{286}{1000}$

Then we simplify the fraction
(286 ÷ 2)/(1000÷2) = 143/500

Therefore,
$9.286 = 9 \frac{286}{1000}$
$9.286 = 9 \frac{143}{500}$

Amiraneli [1.4K]3 years ago

8 0

Hello there,

9.286=9 286/1000--> <span><span>9 143/500</span></span>

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What additional information can be used to prove ΔDSB ≅ ΔTSR by SAS?

Elden [556K]

Please find the attached file for a proper understanding of the question given here. The diagram in the file attached is the complete accompanying diagram of the question.

As per that diagram, $RS\cong SB$ (which is given)

and we know that $\angle DSB\cong \angle RST$ (vertically opposite angles).

Thus, the only way ΔDSB ≅ ΔTSR by SAS is when $DS\cong ST$ as indicated in the diagram.

Thus, $DS\cong ST$ is the correct answer.

8 0

3 years ago

Read 2 more answers

A cylinder shaped can needs to be constructed to hold 500 cubic centimeters of soup. The material for the sides of the can costs

iogann1982 [59]

Answer:

r=3.628cm

h=12.093cm

Step-by-step explanation:

For this problem we are going to use principles, concepts and calculations from multivariable calculus; mainly we are going to use the Lagrange multipliers method. This method is thought to help us to find a extreme value of a multivariable function 'F' given a restriction 'G'. F represents the function that we want to optimize and G is just a relation between the variables of which F depends. The Lagrange method for just one restriction is:

$\nabla F=\lambda \nabla G$

First, let's build the function that we want to optimize, that is the cost. The cost is a function that must sum the cost of the sides material and the cost of the top and bottom material. The cost of the sides material is the unitary cost (0.03) multiplied by the sides area, which is $A_s=2\pi rh$ for a cylinder; while the cost of the top and bottom material is the unitary cost (0.05) multiplied by the area of this faces, which is $A_{TyB}=2\pi r^2$ for a cylinder.

So, the cost function 'C' is:

$C=2\pi rh*0.03+2\pi r^2*0.05\\C=0.06\pi rh+0.1\pi r^2$

The restriction is the volume, which has to be of 500 cubic centimeters:

$V=500=\pi r^2h\\500=\pi hr^2$

So, let's apply the Lagrange multiplier method:

$\nabla C=\lambda \nabla V\\\frac{\partial C}{\partial r}=0.06\pi h+0.2\pi r\\\frac{\partial C}{\partial h}=0.06\pi r\\\frac{\partial V}{\partial r}=2\pi rh\\\frac{\partial V}{\partial h}=\pi r^2\\(0.06\pi h+0.2\pi r,0.06\pi r)=\lambda (2\pi rh,\pi r^2)$

At this point we have a three variable (h,r, λ)-three equation system, which solution will be the optimum point for the cost (the minimum). Let's write the system:

$0.06\pi h+0.2\pi r=2\lambda \pi rh\\0.06\pi r=\lambda \pi r^2\\500=\pi hr^2$

(In this kind of problems always the additional equation is the restricion, in this case, V=500).

Let's divide the first and second equations by π:

$0.06h+0.2r=2\lambda rh\\0.06r=\lambda r^2\\500=\pi hr^2$

Isolate λ from the second equation:

$\lambda =\frac{0.06}{r}$

Isolate h from the third equation:

$h=\frac{500}{\pi r^2}$

And then, replace λ and h in the first equation:

$0.06*\frac{500}{\pi r^2} +0.2r=2*(\frac{0.06}{r})r\frac{500}{\pi r^2} \\\frac{30}{\pi r^2}+0.2r= \frac{60}{\pi r^2}$

Multiply all the resultant equation by $\pi r^{2}$ :

$30+0.2\pi r^3=60\\0.2\pi r^3=30\\r^3=\frac{30}{0.2\pi } =\frac{150}{\pi}\\r=\sqrt[3]{\frac{150}{\pi}}\approx 3.628cm$

Then, find h by the equation $h=\frac{500}{\pi r^2}$ founded above:

$h=\frac{500}{\pi r^2}\\h=\frac{500}{\pi (3.628)^2}=12.093cm$

4 0

3 years ago

A desk is on sale for $380 which is 20% of the original price. Which equation can be used to determine the amount of money saved

elena-s [515]

Answer:

S = 380 - 380*80%

Step-by-step explanation:

Given:

The original price of the desk: $380
Discount: 20%

So, the new price of the desk after discounting is:

380(100% - 20%)

= 380*80%

= 304$

The amount of money saved: 380 - 304 = 76$

Hence, the equation can be used to determine the amount of money saved is:

Saving = 380 - 380*80%

Hope it will find you well.

8 0

3 years ago

Read 2 more answers

Annual snowfall in Anchorage, Alaska, is normally distributed with a mean height of 76 inches and a standard deviation of 4.7 in

lukranit [14]

Answer:

67.75%

Step-by-step explanation:

Given:

Given that:

µ = 76 ; σ = 4.7

P(x < 80.7) - P(x < 71.4)

Obtain the standardized score, Z ; x = 71. 4

Zscore = (x - μ) / σ

P(x < 71.4) = (71.4 - 76) / 4.7

P(x < 71.4) = - 4.6 / 4.7

P(x < 71.4) = - 0.9787

P(z < 0.9787) = 0.16386

x = 80.7

P(x < 80.7) = (80.7 - 76) / 4.7

P(x < 80.7) = 4.7 / 4.7

P(x < 80.7) = 1

P(z < 1) = 0.84134

0.84134 - 0.16386 = 0.67748 = 67.748% = 67.75%

6 0

2 years ago

On a coordinate plane, 2 lines are shown. Line P Q has points (negative 8, 2) and (4, 2). Line M N has points (8, 6) and (8, neg

DaniilM [7]

Answer:

Slope of PQ = 0

Slope of MN = infinity

PQ and MN are perpendicular to each other

Step-by-step explanation:

for any two points (x1, y1), (x2, y2)given in coordinate plane slope is given by

$y1 - y2/x1-x2\\\\For \ line \ PQ\\slope = 2 - 2/-8-4 = 0\\\\For \ line \ MN \\slope = 6 - (-8)/8-8 = 1/0 = infinity\\\\$

For any line if slope is zero it is parallel to X axis and perpendicular to Y axis

For any line if slope is infinity it is parallel to Y axis and perpendicular to X axis

Also we know X and Y are perpendicular to each other.

Since slope of PQ is zero it is parallel to X axis and perpendicular to Y axis

Since slope of MN is infinity it is parallel to Y axis and perpendicular to X axis.

Thus two lines PQ and MN are perpendicular to each other.

4 0

3 years ago

Read 2 more answers