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Sever21 [200]
3 years ago
12

The slope of a line parallel to y=1/2x-4 is ?

Mathematics
2 answers:
stealth61 [152]3 years ago
6 0

Answer:

1/2x

Step-by-step explanation:

For lines to be parallel, the has to always remain the same because they both are moving at a constant rate and will never intercept but they need a different y-intercept.

Dmitry [639]3 years ago
3 0

Answer:

1/2x

Step-by-step explanation:

y=1/2x-4

1/2x is the slope, x is the slope in any linear equation

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Find the missing number:
nirvana33 [79]

Answer:

20%

Step-by-step explanation:

Not sure if this is exactly correct, but let's say we start with 1 unit. If it increased by 25%, we get:

1 × 1.25 = 1.25 units.

Now, to get back to 1 unit, we need to find:

1.25 × ?  = 1

? = \frac{1}{1.25} = 0.80

So, 100% - 80 % = 20%

A 20% decrease.

Not completely sure though.

8 0
3 years ago
Each of these extreme value problems has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to f
tino4ka555 [31]

Answer:

The minimum value of the given function is f(0) = 0

Step-by-step explanation:

Explanation:-

Extreme value :-  f(a, b) is said to be an extreme value of given function 'f' , if it is a maximum or minimum value.

i) the necessary and sufficient condition for f(x)  to have a maximum or minimum at given point.

ii)  find first derivative f^{l} (x) and equating zero

iii) solve and find 'x' values

iv) Find second derivative f^{ll}(x) >0 then find the minimum value at x=a

v) Find second derivative f^{ll}(x) then find the maximum value at x=a

Problem:-

Given function is f(x) = log ( x^2 +1)

<u>step1:</u>- find first derivative f^{l} (x) and equating zero

  f^{l}(x) = \frac{1}{x^2+1} \frac{d}{dx}(x^2+1)

f^{l}(x) = \frac{1}{x^2+1} (2x)  ……………(1)

f^{l}(x) = \frac{1}{x^2+1} (2x)=0

the point is x=0

<u>step2:-</u>

Again differentiating with respective to 'x', we get

f^{ll}(x)=\frac{x^2+1(2)-2x(2x)}{(x^2+1)^2}

on simplification , we get

f^{ll}(x) = \frac{-2x^2+2}{(x^2+1)^2}

put x= 0 we get f^{ll}(0) = \frac{2}{(1)^2}   > 0

f^{ll}(x) >0 then find the minimum value at x=0

<u>Final answer</u>:-

The minimum value of the given function is f(0) = 0

5 0
3 years ago
Help please I don't under stand number 7
vlabodo [156]
You dived by the bottom fraction and once again. dived by 12 because ft to inches 12 and you know the order of numbers hope this helps!
4 0
3 years ago
HELPPPP PLEASEEEEEEEEWEE HELPPPPPPPP
Nookie1986 [14]

Answer:

calculate the rise over the run.

therefore, it's -8/7

Topic: coordinate geometry

If you like to venture further, do check out my insta (learntionary) where I regularly post useful math tips! Thank you!

4 0
3 years ago
Read 2 more answers
What is the Answer <br> Please Help
sergejj [24]

Answer:

Step-by-step explanation:

circumference=2πr

=2*3.14*2

=12.56 km

3 0
2 years ago
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