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il63 [147K]
3 years ago
10

What is the probability of getting 53 Sundays in a Leap year? Please explain with all the steps.

Mathematics
1 answer:
Vaselesa [24]3 years ago
8 0
What is the probability, that a leap year selected at random will contain 53 Sundays? 

Sol.: A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days.

The remaining 2 days may be any of the following : 

(i) Sunday and Monday 

(ii) Monday and Tuesday 

(iii) Tuesday and Wednesday 

(iv) Wednesday and Thursday 

(v) Thursday and Friday 

(vi) Friday and Saturday 

(vii) Saturday and Sunday 

For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday. 

n(S) = 7 

n(E) = 2 

<span>P(E) = n(E) / n(S) = 2 / 7


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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john currently has enough money to buy 45 books. If the cost of each book was 10 cents less.john could buy 5 more books. How muc
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Let the cost of one book= x cents
Let the money john have= y cents

According to the question,

45x=y                                               ...eq(1)
(45+5)(x-5)=y                                  
50(x-5)=y                                         
50x-250=y                                        ...eq(2)

On subtracting (1) from (2).
(50x-250)-45x=y-y
5x-250=0
x=250/5
x=50

Thus, cost of each book is 50 cents and john has 2250 cents.

Hope it helps.
Don't feel shy in saying thx if it helps.


4 0
3 years ago
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katrin2010 [14]
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4 0
3 years ago
Please help. I need to get this right.
babunello [35]

Answer:

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3 0
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Answer:

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