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Akimi4 [234]
3 years ago
7

PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPp

Mathematics
1 answer:
kherson [118]3 years ago
3 0

1. is just 6

2.3/13

3.325/28=11.607

5.16oz i think

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If W(-10, 4), X(-3, -1), and Y(-5, 11) classify ΔWXY by its sides. Show all work to justify your answer.
solniwko [45]

Given:

The vertices of ΔWXY are W(-10, 4), X(-3, -1), and Y(-5, 11).

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Which type of triangle is ΔWXY by its sides.

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Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using distance formula, we get

WX=\sqrt{(-3-(-10))^2+(-1-4)^2}

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WX=\sqrt{(7)^2+(-5)^2}

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XY=\sqrt{\left(-5-\left(-3\right)\right)^2+\left(11-\left(-1\right)\right)^2}=2\sqrt{37}

WY=\sqrt{\left(-5-\left(-10\right)\right)^2+\left(11-4\right)^2}=\sqrt{74}

Now,

WX=WY

So, triangle is an isosceles triangles.

and,

WX^2+WY^2=(\sqrt{74})^2+(\sqrt{74})^2

WX^2+WY^2=74+74

WX^2+WY^2=148

WX^2+WY^2=(2\sqrt{37})^2

WX^2+WY^2=WY^2

So, triangle is right angled triangle.

Therefore, the ΔWXY is an isosceles right angle triangle.

3 0
2 years ago
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