Let, length and breadth of rectangle is L and B respectively.
It is given that :
The length rectangle is 4 cm more than 3 times the width of the rectangle.
L = 3B + 4 ......1 )
Also, area of square = area of the rectangle + 66
L² = LB + 66
Putting value of L from
L² = ( 3B + 4 )( B ) + 66
L² = 3B² + 4B + 66
( 3B + 4 )² = 3B² + 4B + 66
9B² + 16 + 24B = 3B² + 4B + 66
6B² + 20B - 50 = 0
3B² + 10B - 25 = 0
3B² + 15B - 5B -25 = 0
3B( B + 5 ) -5( B + 5 ) = 0
B = 5/3 units
L = 3( 5/3 ) + 4
L = 5 + 4 = 9 units
Hence, this is the required solution.
Answer:
$1200 interest
Step-by-step explanation:
$30,000 divided by 100 = 300 , 300 multipled by 4 = 1200 , thats how to find what 4% would be
<span>(4x ÷ 2) - 9y
is difference of two terms.</span>
y = A(Bx - C)ⁿ + D
A is a vertical stretch (or shrink if |A| < 1)
B is a vertical shrink (or stretch if |B| < 1)
C is a shift to the right (or left if C is negative) → notice that Bx - C is "-C" so to take the opposite
D is a shift up (or down if D is negative)
when C = -3, it is a shift to the left 3 units
when D = -7, it is a shift down 7 units
Answer: B