Answer:
A real world situation could be: Holden is walking to school for his basketball game.
He lives 10 blocks from school. Holden walks 6 blocks in 4 minutes, but then realizes that he forgot his jersey. He runs back home in 2 minutes and spends 2 minutes finding his jersey at home. Finally, he runs 5 blocks every 2 minutes until he reaches school. And a good example/photo would be: (down below)
Step-by-step explanation:
I hope this helps! brainliest?
Ok so here we go!
a steam and leaf plot is very simple to figure out
for example if a number was 6|4 it would equal 64
so for your first question range equals the biggest number subtracted by the smallest number so in your case it would be 28-55
which equals 27
If you've started pre-calculus, then you know that the derivative of h(t)
is zero where h(t) is maximum.
The derivative is h'(t) = -32 t + 96 .
At the maximum ... h'(t) = 0
32 t = 96 sec
t = 3 sec .
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If you haven't had any calculus yet, then you don't know how to
take a derivative, and you don't know what it's good for anyway.
In that case, the question GIVES you the maximum height.
Just write it in place of h(t), then solve the quadratic equation
and find out what 't' must be at that height.
150 ft = -16 t² + 96 t + 6
Subtract 150ft from each side: -16t² + 96t - 144 = 0 .
Before you attack that, you can divide each side by -16,
making it a lot easier to handle:
t² - 6t + 9 = 0
I'm sure you can run with that equation now and solve it.
The solution is the time after launch when the object reaches 150 ft.
It's 3 seconds.
(Funny how the two widely different methods lead to the same answer.)
The answer is from AL2006
Answer:
4 and 1/4 i think
Step-by-step explanation:
