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Eddi Din [679]
3 years ago
5

Please help me out with this

Mathematics
1 answer:
ladessa [460]3 years ago
4 0

Formula of the point-slope equation for the right line that passes through two points is

y-y1=(y2-y1)/(x2-x1)*(x-x1)   In our case  (x1,y1)=(-10,-20) and (x2,y2)=(1,-9)

y-(-20)=(-9-(-20))/(1-(-10))*(x-(-10)) => y+20=(-9+20)/(1+10)*(x+10) =>

y+20= 11/11*(x+10) => y+20=x+10 => y=x-10

Good luck!!!

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f(x)=x3−5

Replace f(x)

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y=x3−5

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x=y3−5

Solve for y

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Since y

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y3−5=x

Add 5

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y3=5+x

Take the cube root of both sides of the equation to eliminate the exponent on the left side.

y=3√5+x

Solve for y

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Replace the y

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f−1(x)=3√5+x

Set up the composite result function.

f(g(x))

Evaluate f(g(x))

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(3√5+x)3−5

Simplify each term.


Remove parentheses around 3√5+x

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f(3√5+x)=3√5+x3−5

Rewrite 3√5+x3

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f(3√5+x)=5+x−5

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f(3√5+x)=x+0

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f−1(x)=3√5+x

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