Answer:
Whoa
Explanation:
What the blankkkk is this
Answer:
Check the explanation
Explanation:
Kindly check the attached images below to see the step by step explanation to the question above.
Answer:
1. There most not be rotation within the molecule.
2. Two non identical group must be present in the double bonded carbon atom.
Explanation:
This is because cis/ trans isomerism are that exhibit different structural configurations where the atoms are spartially arranged. They are also refered to as geometric isomers. They cannot be interconverted at room temperature because it requires the bonds to be broken and restructured.
Cis shows that the functional groups on present in the same side which trans isomerism show that the functional groups are on opposite sides.
Answer:
1)50.007 grams of an isotope will left after 10 years.
1)25.007 grams of an isotope will left after 20 years.
3) 23 half-lives will occur in 40 years.
Explanation:
Formula used :
![N=N_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}](https://tex.z-dn.net/?f=N%3DN_o%5Ctimes%20e%5E%7B-%5Clambda%20t%7D%5C%5C%5C%5C%5Clambda%20%3D%5Cfrac%7B0.693%7D%7Bt_%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D)
where,
= initial mass of isotope
N = mass of the parent isotope left after the time, (t)
= half life of the isotope
= rate constant
We have:
![[N_o]=100 g](https://tex.z-dn.net/?f=%5BN_o%5D%3D100%20g)
![t_{1/2}=10 years](https://tex.z-dn.net/?f=t_%7B1%2F2%7D%3D10%20years)
![\lambda =\frac{0.693}{t_{1/2}}=\frac{0.693}{10 year}=0.0693 year^{-1}](https://tex.z-dn.net/?f=%5Clambda%20%3D%5Cfrac%7B0.693%7D%7Bt_%7B1%2F2%7D%7D%3D%5Cfrac%7B0.693%7D%7B10%20year%7D%3D0.0693%20year%5E%7B-1%7D)
1) mass of isotope left after 10 years:
t = 10 years
![N=N_o\times e^{-\lambda t}](https://tex.z-dn.net/?f=N%3DN_o%5Ctimes%20e%5E%7B-%5Clambda%20t%7D)
![N=100g\times e^{-0.0693 year^{-1}\times 10}=50.007 g](https://tex.z-dn.net/?f=N%3D100g%5Ctimes%20e%5E%7B-0.0693%20year%5E%7B-1%7D%5Ctimes%2010%7D%3D50.007%20g)
2) mass of isotope left after 20 years:
t = 20 years
![N=N_o\times e^{-\lambda t}](https://tex.z-dn.net/?f=N%3DN_o%5Ctimes%20e%5E%7B-%5Clambda%20t%7D)
![N=100g\times e^{-0.0693 year^{-1}\times 20}=25.007 g](https://tex.z-dn.net/?f=N%3D100g%5Ctimes%20e%5E%7B-0.0693%20year%5E%7B-1%7D%5Ctimes%2020%7D%3D25.007%20g)
3) Half-lives will occur in 40 years
Mass of isotope left after 40 years:
t = 40 years
![N=N_o\times e^{-\lambda t}](https://tex.z-dn.net/?f=N%3DN_o%5Ctimes%20e%5E%7B-%5Clambda%20t%7D)
![N=100g\times e^{-0.0693 year^{-1}\times 40}=6.2537 g](https://tex.z-dn.net/?f=N%3D100g%5Ctimes%20e%5E%7B-0.0693%20year%5E%7B-1%7D%5Ctimes%2040%7D%3D6.2537%20g)
number of half lives = n
![N=\frac{N_o}{2^n}](https://tex.z-dn.net/?f=N%3D%5Cfrac%7BN_o%7D%7B2%5En%7D)
![6.2537 g=\frac{100 g}{2^n}](https://tex.z-dn.net/?f=6.2537%20g%3D%5Cfrac%7B100%20g%7D%7B2%5En%7D)
![n\ln 2=\frac{100 g}{6.2537 g}](https://tex.z-dn.net/?f=n%5Cln%202%3D%5Cfrac%7B100%20g%7D%7B6.2537%20g%7D)
n = 23
23 half-lives will occur in 40 years.
Sorry so what I think u should do is ask your teach or look up on how to do this problem