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3 years ago

1.) You have a beaker with 8 grams of (NH4)2CO3 in it. How many atoms are in the beaker?

Chemistry

2 answers:

denpristay [2]3 years ago

6 0

Answer:

The answer to your question is 5.019 x 10²² atoms

Explanation:

Data

mass of ammonium carbonate = 8 g

number of atoms = ?

Process

1.- Calculate the molar mass of (NH₄)₂CO₃

(NH₄)₂CO₃ = (14 x 2) + (1 x 8) + (12 x 1) + (16 x 3)

= 28 + 8 + 12 + 48

= 96 g

2.- Calculate the number of atoms

96 g ------------------ 6.023 x 10²³ atoms

8 g ----------------- x

x = (8 x 6.023 x 10²³) / 96

x = 5.019 x 10²² atoms

Nina [5.8K]3 years ago

3 0

Answer:

There are 5.02*10^22 atoms in the beaker

Explanation:

Step 1: Data given

Mass of (NH4)2CO3 = 8.0 grams

Molar mass (NH4)2CO3 = 96.09 g/mol

Number of Avogadro = 6.022 *10^23 / moles

Step 2: Calculate moles (NH4)2CO3

Moles (NH4)2CO3 = mass (NH4)2CO3 / molar mass

Moles (NH4)2CO3 = 8.0 grams / 96.09 g/mol

Moles (NH4)2CO3 = 0.0833 moles

Step 3: Calculate atoms

Atoms = moles * number of Avogadro

Atoms = 0.0833 moles * 6.022 * 10^23 / mol

Atoms = 5.02 *10^22 atoms

There are 5.02*10^22 atoms in the beaker

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ra1l [238]

A. is the answer

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3 years ago

2NaOH + H2SO4 ------> 2 H2O + Na2SO4

balandron [24]

$\huge\fbox{Answer ☘}$

It is given in the question that 200.0 grams of sodium hydroxide reacts with excess of sulphuric acid.

The given reaction is shown below

$\bold\blue{2NAOH + H _{2}SO _{4} \: - > 2H _{2} O+ NA _{2}SO_{4} }\\$

In this reaction, two mole of sodium hydroxide react with one mole of sulphuric acid to give two mole of water and one mole of sodium sulfate.

To determine the mass of sodium sulfate, first calculate the moles of sodium hydroxide as the value of mass is provided.

The molecular weight of NaOH is 40 g/mol.

The formula is shown below.

$\pink{n = \frac{m}{ M}}\\$

Where,

✫ n is the number of moles

✫ m is the mass

✫ M is the molecular weight

To calculate the number of moles, substitute the values in the above equation.

$\pink{n = \frac{200.0}{40g \: mol {}^{ - 1} } } \\ \\\pink{ ⇢n = 5}$

In the equation it is given that 2 mole of sodium hydroxide gives 1 mole of sodium sulphate.

So, to determine the actual mole of sodium sulfate divide the calculated moles of NaOH by 2.

$\pink{⇢ \frac{5}{2}} \\ \\ \pink{⇢ 2.5 \: mol}$

So 2.5 mol sodium sulfate is formed from 5 mol NaOH.

The molecular weight of sodium sulfate is 142.1 g/mol.

To calculate the mass of sodium sulfate, substitute the values in the formula.

$\pink{⇢2.5 = \frac{m}{142.1g \: mol {}^{ - 1} } } \\ \\\pink{ ⇢ m = 2.5 \times 142.1 }\\ \\ \pink{⇢ m = 355.25}$

Therefore, the mass of sodium sulfate formed when we start with 200.0 grams of sodium hydroxide and you have excess sulphuric acid is 355.25g.

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5 0

2 years ago

How much hbro must be added to 1l of pure water to make a solution with a ph of 4.25? ka = 2.00 × 10−9 ?

RUDIKE [14]

Answer is: 153.52 grams of hypobromous acid <span>must be added.
</span>Chemical dissociation: HBrO ⇄ H⁺ + BrO⁻.
pH = 4.25.
pH = -log[H⁺].
[H⁺] = 10∧(-pH).
[H⁺] = 10∧(-4.25).
[H⁺] = [BrO⁻] = 5.62·10⁻⁵ M.
Ka = [H⁺] · [BrO⁻] / [HBrO].
2.00·10⁻⁹ = (5.62·10⁻⁵ M)² / [HBrO].
[HBrO] = 3.16·10⁻⁹ M² / 2.00·10⁻⁹.
[HBrO] = 1.58 M.
m(HBrO) = n(HBrO) · M(HBrO).
m(HBrO) = 1.58 mol · 96.91 g/mol.
m(HBrO) = 153.52 g.

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4 years ago

The function of most proteins depends primarily on the

sineoko [7]

<span>type and order of amino acids</span>

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4 years ago

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The chemist discovers a more efficient catalyst that can produce ethyl butyrate with a 78.0% yield. How many grams would be prod

Vedmedyk [2.9K]

The grams that would be produced from 7.70 g of butanoic acid and excess ethanol is 7.923grams

calculation

Step 1: write the chemical equation for the reaction

CH3CH2CH2COOH + CH3CH2OH → CH3CH2CH2COOCH2CH3 +H2O

step 2: find the moles of butanoic acid

moles= mass/ molar mass

= 7.70 g/ 88 g/mol=0.0875 moles

Step 3: use the mole ratio to determine the moles of ethyl butyrate

moles ratio of CH3CH2CH2COOH :CH3CH2CH2COOCH2CH3 is 1:1 therefore the moles of CH3CH2CH2COOCH2CH3 = 0.0875 x78/100=0.0683moles

step 4: find mass = moles x molar mass

= 0.0683 moles x116 g/mol=7.923grams

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3 years ago

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