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julsineya [31]
3 years ago
11

A first number plus twice a second number is 9. Twice the first number plus the second totals 21. Find the numbers

Mathematics
1 answer:
WITCHER [35]3 years ago
7 0
Let x and y be the numbers;
We have x + 2y = 9 and 2x + y = 21;
Then, x = 9 - 2y;
Finally, 2(9-2y) + y = 21 ;
18 - 4y + y = 21;
18 - 3y = 21;
-3y = 3;
y = - 1;
x = 9 - 2× (-1);
x = 9 + 2 ;
x = 11;
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Using it's formula, it is found that the monthly payments for the loan of the apartment is of $7,260.50.

<h3>What is the monthly payment formula?</h3>

It is given by:

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Then, the monthly payments will be of:

A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}

A = 500000\frac{0.01025(1+0.01025)^{120}}{(1+0.01025)^{120} - 1}

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2 years ago
A perpendicular bisector, , is drawn through point C on .
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Answer:

The x-intercept of CD is B(18/5,0). The point C(32,-71) lies on the line CD.

Step-by-step explanation:

the x-intercept of CD is[ A(3,0) B(18/5,0) C(9,0) D(45/2,0) ] . Point [ A(-52,117) B(-20,57) C(32,-71) D(-54,-128) ] lies on CD.

Given :

CD is perpendicular bisector of AB.

The coordinates of point A are (-3, 2) and the coordinates of point B are (7, 6).

C is the midpoint of AB.

C=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})=(\frac{7-3}{2},\frac{2+6}{2})=(2,4)

The coordinates of C are (2,4).

Line AB has a slope of:m_1=\frac{y_2-y_1}{x_2-x_1}=\frac{6-2}{7-(-3)}=\frac{4}{10}=\frac{2}{5}

The product of slopes of two perpendicular lines is -1. Since the line CD is perpendicular to AB, therefore the slope of CD : m_2=-\frac{5}{2}

The point slope form of a line is given by:

y-y_1=m(x-x_1)

The slope of line CD is -\frac{5}{2} and the line passing through the point (2,4), the equation of line CD can be written as:

y-4=-\frac{5}{2}(x-2)\\y=-\frac{5}{2}x+5+4\\y=-\frac{5}{2}x+9       .... (1)

The equation of CD is y=-\frac{5}{2}x+9

In order to find the x-intercept, put y=0.

0=-\frac{5}{2}x+9\\\frac{5}{2}x=9\\x=\frac{18}{5}

Therefore the x-intercept of CD is B(18/5,0).

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y=-\frac{5}{2}(-52)+9=139

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y=-\frac{5}{2}(-20)+9=59

Put x=32 in eq(1)

y=-\frac{5}{2}(32)+9=-71

Put x=-54 in eq1).

y=-\frac{5}{2}(-54)+9=144

Thus, only point (32,-71) satisfies the equation of CD. Therefore the point C(32,-71) lies on the line CD.

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