Check the picture below.
so the picture has a rectangle that is 8 units high and 12 units wide, and it has a couple of "empty" trapezoids, with a height of 5 and "bases" of 9 and 3.
now, if we just take the whole area of the rectangle and then subtract the area of those two trapezoids, what's leftover is the blue area.
![\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{parallel~sides}{bases}\\[-0.5em] \hrulefill\\ h=5\\ a=9\\ b=3 \end{cases}\implies \begin{array}{llll} A=\cfrac{5(9+3)}{2}\implies A=30 \end{array} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\large Areas}}{\stackrel{rectangle}{(12\cdot 8)}~~ -~~\stackrel{\textit{two trapezoids}}{2(30)}}\implies 96-60\implies 36](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20h%3Dheight%5C%5C%20a%2Cb%3D%5Cstackrel%7Bparallel~sides%7D%7Bbases%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20h%3D5%5C%5C%20a%3D9%5C%5C%20b%3D3%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%20A%3D%5Ccfrac%7B5%289%2B3%29%7D%7B2%7D%5Cimplies%20A%3D30%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7B%5Clarge%20Areas%7D%7D%7B%5Cstackrel%7Brectangle%7D%7B%2812%5Ccdot%208%29%7D~~%20-~~%5Cstackrel%7B%5Ctextit%7Btwo%20trapezoids%7D%7D%7B2%2830%29%7D%7D%5Cimplies%2096-60%5Cimplies%2036)
Ratios can be written as fractions.....so the ratio of black keys to white keys is 6:8...which can be written as 6/8....which reduces to 3/4...hence the ratio simplified is 3:4......which is also written as 3/4 and as 3 to 4
Answer:
- Tables A and B represent linear relationship
-------------------------
<h3>Table A</h3>
- x = 2, 3, 4, 5 Difference is 1
- y = 14, 21, 28, 35 Difference is 7
- This is linear and the slope is 7
<h3>Table B</h3>
- x = -2, -1, 0, 1 Difference is 1
- y = 10, 5, 0, -5 Difference is - 5
- This is linear and the slope is - 5
<h3>Table C</h3>
- x = 2, 3, 4, 5 Difference is 1
- y = 48, 72, 90, 114 Difference is inconsistent
Answer:
13ft
Step-by-step explanation:
Kindly find attached a rough draft of the situation.
Step one:
Given data
The length of the slide represents the
Hypotenuse of the situation on the rough sketch
Angle =33°
Required
The height of the ladder which is the adjacent of the rough sketch represented by x
Step two:
Applying SOH CAH TOA
Cos θ= adj/hyp
Cos 33=x/15
0.84=x/15
Cross multiplying
x=0.84*15
x=12.6
To the nearest foot the ladder is 13ft tall
D- 1/4
The probability of Blue shirt blue socks is 1/4 * 1/2 = 1/8
Add this to the same probability of black and black =2/8 = 1/4