A 1000 Kg car traveling at 10 m/s hits the back of a 5000 Kg truck
1 answer:
Answer:
0 m/s
The car becomes stationary
Explanation:
The law of conservation of linear momentum states that the sum of inital and final momentum should be equal and expressed as
Where m represent the mass, u and v are tge initial and final velocities while subscripts c and t represent car and truck.
Taking forward direction as positive then considering that the truck is originally at rest, we substitute original truck velocity with 0, mass of car and truck with 1000 kg and 5000 kg respectively then final truck velocity as 2 m/s as we take initial car velocity to be 10 m/s
1000*10+(5000*0)=5000*2+1000v
1000v=0
V=0
Therefore, the car finally becomes stationary.
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Answer:
Yes, if the two carts are moving into opposite directions
Explanation:
The total momentum of the system of two carts is given by:
where
m1, m2 are the masses of the two carts
v1, v2 are the velocities of the two carts
Let's remind that v (the velocity) is a vector, so its sign depends on the direction in which the cart is moving.
We want to know if it is possible that the total momentum of the system can be zero, so it must be:
From this equation, we see that this condition can only occur if v1 and v2 have opposite signs. Opposite signs mean opposite directions: therefore, the total momentum can be zero if the two carts are moving into opposite directions.
Answer:
W = 157.5kJ
Explanation:
Assuming it moves the container at constant speed, the work done by the crane will be equal to the variation of the potential gratitational energy on the container:
where h2= -8m and h1=0m
Wc = 157.5kJ