A 1000 Kg car traveling at 10 m/s hits the back of a 5000 Kg truck
1 answer:
Answer:
0 m/s
The car becomes stationary
Explanation:
The law of conservation of linear momentum states that the sum of inital and final momentum should be equal and expressed as
Where m represent the mass, u and v are tge initial and final velocities while subscripts c and t represent car and truck.
Taking forward direction as positive then considering that the truck is originally at rest, we substitute original truck velocity with 0, mass of car and truck with 1000 kg and 5000 kg respectively then final truck velocity as 2 m/s as we take initial car velocity to be 10 m/s
1000*10+(5000*0)=5000*2+1000v
1000v=0
V=0
Therefore, the car finally becomes stationary.
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Answer:
Uncertainty in position of the bullet is
Explanation:
It is given that,
Mass of the bullet, m = 35 g = 0.035 kg
Velocity of bullet, v = 709 m/s
The uncertainty in momentum is 0.20%. The momentum of the bullet is given by :
Uncertainty in momentum is,
We need to find the uncertainty in position. It can be calculated using Heisenberg uncertainty principal as :
Hence, this is the required solution.