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Yuki888 [10]
1 year ago
12

For what angle of incidence at the first mirror will this ray strike the midpoint of the second mirror (which is s = 28.8 cm lon

g) after reflecting from the first mirror?
Physics
1 answer:
Naily [24]1 year ago
4 0

The angle of incidence at the first mirror will this ray strike the midpoint of the second mirror is 34.6°

Two plane mirrors intersect at right angles. A laser beam strikes the first of them at a point d = 10.0cm from their point of intersection.

To strike the midpoint of the second mirror, the ray of light will have to travel half of the distance vertically

i.e. 29/2 = 14.5

We can solve this through trigonometry.

Let the angle between the ray and the vertical plane mirror is known as α

tan α = 10/14.5

α =  = 34.6°

The angle of incidence is the angle between the ray and the normal line of the mirror.

Let the angle of incidence of the first mirror be β

β = α = 34.6

Know More about the angle of incidence at:

brainly.com/question/18772331

#SPJ4

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The acceleration of the car will be needed in order to calculate the time. It is important to consider that the final speed is equal to zero:

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Two boats leave the same port at the same time, with boat A traveling north at 15 knots (nautical miles per hour) and boat B tra
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\displaystyle{2s\frac{ds}{dt}= 2x_B\frac{dx_B}{dt}+2y_A\frac{dy_A}{dt}}  (3)

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\displaystyle{y_A = v_A\cdot t\rightarrow t = \frac{y_A}{v_A}=\frac{30}{15}=2 h

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\displaystyle{x_B = v_B\cdot t= 20 \cdot 2 = 40\ nmi

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\displaystyle{s = \sqrt{x_B^2+y_A^2}=\sqrt{30^2 + 40^2}=\sqrt{2500}=50}

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\displaystyle{\frac{ds}{dt} = \frac{1}{2s}(2x_B\frac{dx_B}{dt}+2y_A\frac{dy_A}{dt})}\\\displaystyle{\frac{ds}{dt} = 25 \ knots}

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