The power that must be delivered to the object by the force is 50 W
Power is defined as the rate of doing work. The power of an object in relation to the force and velocity is given by the following equation:
Power (P) = Force (F) × velocity (v)
P = F × v
From the question given above, the following data were obtained:
- Force (F) = 10 N
- Velocity (v) = 5 m/s
- Power (P) =?
P = F × v
P = 10 × 5
<h3>P = 50 W </h3>
Thus, the power that must be delivered to the object by the force is 50 W
Learn more on power: brainly.com/question/19539420
The movie Star Wars<span> is a space
opera interstellar epic which uses science and technology in its settings and storylines, although its main
focus is not necessarily on science.</span>
Many
elements in the films appear to defy simple laws of physics.<span>
One of which is the falling of spaceships when they are hit by a laser beam.
Experts said, this is one good example because without gravity in space, ships
should travel in the direction of the impact instead of dropping like a stone.</span>
<span>
</span>
Change in temperature = final temperature - Initial temperature
Δt = t₂ - t₁
Δt = 17 - (-6)
Δt = 17 + 6 = 23 f
In short, Your Answer would be Option D
Hope this helps!
Pb, if compared to Ca it is less reactive and it is a transition metal, and is highly stable alone.
Answer:
1) v = 0.45 m/s
2) v = 0.65 m/s
3) v = 0.75 m/s
Explanation:
1) We can find the speed of the object by conservation of energy:


Where:
k: is the spring constant = 280 N/m
v: is the speed of the object =?
m: is the mass of the object = 5.00 kg
x: is the displacement of the spring

2) When the object is 5.00 cm (0.050 m) from equilibrium, the speed of the object is:
3) When the object is at the equilibrium position, the speed of the object is:

I hope it helps you!