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2 years ago

Find the acceleration a body whose velocity increases from 11m/s to 33m/s in 10 seconds

Physics

1 answer:

solong [7]2 years ago

7 0

Answer:

1.1 m/(s)^2

Explanation:

u=11 m/s

v=33 m/s

t=10s

v=u+at

=> 33=22+(a)(10)

=> 33-22=10a

=> 10a=11

=> a=11/10=1.1 m/(s)^2

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A bicyclist of mass 60kg supplies 340W of power while riding into a 5 m/s head wind. The frontal area of the cyclist and bicycle

NikAS [45]

Answer:

87.1 mph

Explanation:

We are given that

Mass,m=60 kg

Power,P=340 W

Speed,v=5 m/s

Area, $A=0.344 m^2$

Drag coefficient, $C_d=0.88$

Coefficient of rolling resistance, $\mu_r=0.007$

Friction force, $f=\mu_rmg=0.007\times 60\times 9.8=4.1 N$

Where $g=9.8 m/s^2$

Let speed of cyclist=v'

Drag force, $F_d=\frac{1}{2}\rho_{air}AC_dv^2$

Density of air, $\rho_{air}=1.225 kg/m^3$

$F_d=\frac{1}{2}\times 1.225\times 0.344\times 0.88(5)^2=4.635N$

Power,P= $(F_d+f)\times v'$

$340=(4.1+4.635) v'=8.735v'$

$v'=\frac{340}{8.735}=38.9m/s$

$v'=87.1 mph$

1 m=0.00062137 miles

1 hour=3600 s

7 0

3 years ago

An 8 kilogram bowling ball is rolling in a straight line toward you. if its momentum is 16 kg* m/s, how fast is it traveling ?

morpeh [17]

From the information given, The mass of the bowling ball is 8 Kilograms and the momentum with which it is moving is 16 kg m/s. We use the formula p = m × v Where p is the momentum, m is the mass and v is the velocity. We need velocity so we rewrite the equation thus: P = mv, therefore p/m = v or v = p/m In our case p = 16 and m = 8 v = p/m v = 16/8 v = 2 Therefore the bowling ball is travelling at 2m/s

6 0

3 years ago

If a 20 N object has been lifted 5 meters above the ground, how much gravitational potential energy does it have?

Andreyy89

The gravitational potential energy of the object is 100 J.

Gravitational potential energy stored in an object is the work done in raising the object to a height <em>h</em> against the gravitational force acting on it.

The gravitational force acting on a body is its weight mg, where m is its mass and g, the acceleration due to gravity.

Work done by a force is equal to the product of the force and the displacement made by the point of application of the force.

$GPE = mgh$