The answer is B
Using the equation, F=MA, we can determine that...
(125kg) (3m/s^2) = 375N
Answer:
Explanation:
First, we can find the mass of the object in air
Since W = mg
m = W/g = (8.9)/(9.8) = 0.908 kg
Then, by Archimedes principle, we can find its volume. The volume is found by the weight of the water displaced by the formula
W = Vρg
The Weight is the difference in scale readings. The density of water is 1000 kg/m3
(8.9- 7.8) = V(1000)(9.8)
Thus V = 1 X 10-4 m3
Then, since density is mass / volume
ρ = 0.908/1 X 10-4
ρ = 8254 kg/m3 which is 8 X 103 kg/m3
The density of gold is 19.3 X 103 kg/m3
Since those densities are not the same, the crown is either hollow or not pure gold
Answer:
9.6 rad/s
Explanation:
= length of the metal rod = 50 cm = 0.50 m
= Mass of the long metal rod = 780 g = 0.780 kg
Moment of inertia of the rod about one end is given as
= force applied by the hammer blow = 1000 N
Torque produced due to the hammer blow is given as
= time of blow = 2.5 ms = 0.0025 s
= Angular velocity after the blow
Using Impulse-change in angular momentum, we have
Answer:
The dimension of the nullspace of T = 4
Explanation:
The rank/dimension theorem is explains that:
Suppose V and W are vector spaces over F, and T:V → W is linear. If V is finite dimensional, then
nullity(T) + rank(T) = dim(V).
rank(T) = dimension of T = dim(T) = dim(W) = 7
nullity(T) = dimension of the nullspace of T = dim(T) = ?
dim(V) = 11
nullity(T) = dim(V) - dim(T) = 11 - 7
nullity(T) = 4.
What are the answer options? It says which of the following. :)
