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DedPeter [7]
3 years ago
6

An electromagnet is a with a core.

Physics
2 answers:
dsp733 years ago
7 0

Answer:

An electromagnet is a magnet that runs on electricity. Unlike a permanent magnet, the strength of an electromagnet can easily be changed by changing the amount of electric current that flows through it. The poles of an electromagnet can even be reversed by reversing the flow of electricity.

dedylja [7]3 years ago
6 0

Answer:

solenoid & metal

Explanation:

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Definition: A potential path for the flow of electricity with at least one gap in the path that prevents this flow. The gap is u
Andreas93 [3]

Answer:

Open circuit

Explanation:

An open circuit is simply an electrical circuit that is not complete. In such a circuit, there is a gap and this will not allow the electric current to pass through.

Despite all the elements being complete in the circuit, an open circuit will halt the flow of electric current and will not do deliver the necessary energy it is supposed to.

In such a circuit, the wires are cut of and not connected properly.

The reverse is a closed circuit.

7 0
3 years ago
Read 2 more answers
Spaceship A is 10 meters long and approaching you from the south at a speed of.7c while spaceship B, which is also 10 meters lon
Valentin [98]

Answer:

a) 0.94 C

b) 7.14 m

c) 3.11 m

d) 1.40 s

e) 2.93 s

Explanation:

First we need to set up a coordinate system. This will have the positive X axis pointing north. So spaceship A has positive speed, and spaceship B has negative speed.

The Lorentz transformation for speed is:

u' = \frac{u - v}{1 - \frac{u*v}{c^2}}

u: speed of spaceship A as observed by you

v: speed of spaceship B as observed by you

In the case of the speed of spaceship A as observed by spaceship B:

u' = \frac{0.7c - (-0.7c)}{1 - \frac{0.7c*(-0.7c)}{c^2}} = 0.94c

The transform for lengths is:

L = L0 * \sqrt{1 - \frac{v^2}{c^2}}

For the case of spaceship A as observed by you:

L = 10 m * \sqrt{1 - \frac{(0.7c)^2}{c^2}} = 7.14 m

For the case of spaceship A as observed by spaceship B:

L = 10 m * \sqrt{1 - \frac{(0.94c)^2}{c^2}} = 3.12 m

The time dilation equation is:

T = \frac{T0}{\sqrt{1-\frac{v^2}{c^2}}}

For the case of the event as observed by you:

\frac{1 s}{\sqrt{1-\frac{(0.7c)^2}{c^2}}} = 1.40 s

For the case of the event as observed by spaceship B:

\frac{1 s}{\sqrt{1-\frac{(0.94c)^2}{c^2}}} = 2.93 s

3 0
3 years ago
A coin with a diameter of 2.40 cm is dropped on edge onto a horizontal surface. The coin starts out with an initial angular spee
posledela

Answer:

The coin comes to rest after covering 1.023 m.

Explanation:

initial angular speed, wo = 18 rad/s

final angular speed, w = 0 rad/s

angular acceleration, = 1.9 rad/s2

radius, r = 1.2 cm =  0.012 m

initial linear velocity, u = r wo = 0.012 x 18 = 0.216 m/s

final linear speed, v = r w = 0.012 x 0 = 0 m/s

linear acceleration, a = r x angular acceleration = 0.012 x 1.9 = 0.0228 m/s2

let the distance traveled is s.

Use third equation of motion

v^{2} = u^{2} + 2 a s\\0 = 0.216^{2} - 2 \times 0.0228\times s\\s = 1.023 m

4 0
3 years ago
Electrons are ejected when sodium metal is irradiated with 400 nm light. what is the velocity of the electrons? (φna = 4.4 x 10-
MissTica

Answer: 3.5\cdot 10^5 m/s

Explanation:

In the photoelectric effect, the energy of the incident photon is used partially to extract the photoelectron from the metal (work function) and part is given to the photoelectron as kinetic energy:

hf=\phi +K (1)

where

hf is the energy of the photon, with h being the Planck constant and f the photon frequency

\phi is the work function of the metal

K is the kinetic energy of the electron

In this problem, the photon hasa wavelength of \lambda=400 nm=4 \cdot 10^{-7} m, so its frequency is

f=\frac{c}{\lambda}=\frac{3\cdot 10^8 m/s}{4\cdot 10^{-7} m}=7.5\cdot 10^{14} Hz

Now we can use eq.(1) to find the Kinetic energy of the photoelectron

K=hf-\phi = (6.63\cdot 10^{-34} Js)(7.5\cdot 10^{14} Hz)-4.4\cdot 10^{-19} J)=5.7\cdot 10^{-20} J

And the kinetic energy of the electron is given by:

K=\frac{1}{2}mv^2

From which we can find the electron's velocity:

v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(5.7\cdot 10^{-20}J)}{9.11\cdot 10^{-31} kg}}=3.5\cdot 10^5 m/s

8 0
3 years ago
The product of 2.03 and 0.05​
Colt1911 [192]

Answer:

2.03 x 0.05= 0.1015

.........

5 0
3 years ago
Read 2 more answers
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