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Rudik [331]
3 years ago
10

The alkali metals all react vigorously with water. Which alkali metal would react to the greatest extent if you have equal amoun

ts of each? A) K B) Li C) Na D) Rb
Physics
1 answer:
Vladimir79 [104]3 years ago
8 0
<h3><u>Answer;</u></h3>

<em>-Rubidium (Rb)</em>

<h3><u>Explanation;</u></h3>
  • <em><u>Alkali metals are group 1 elements, </u></em>they have a valency of 1 and react by loosing electrons to attain a stable configuration.
  • <em><u>The reactivity of alkali metals increases down the group, this is due to the increase in the number of energy levels</u></em> which makes it easier for the valence electrons to be lost.
  • Therefore, in our case,<em><u> rubidium will be the most reactive as it contains more number of energy levels</u></em>, therefore it will loose valence electron more easily compared to the other alkali metals above it in the group.

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(b) The wavelength of the photon is 1.2 x 10^{-17} m.

(c) The frequency of the photon is 2.47 x 10^{25} Hz.

Explanation:

Let;

E_{1} = -13.60 ev

E_{2} = -3.40 ev

(a) Energy of the emitted photon can be determined as;

E_{2} - E_{1} = -3.40 - (-13.60)

           = -3.40 + 13.60

           = 10.20 eV

           = 10.20(1.6 x 10^{-9})

E_{2} - E_{1} = 1.632 x 10^{-8} Joules

The energy of the emitted photon is 10.20 eV (or 1.632 x 10^{-8} Joules).

(b) The wavelength, λ, can be determined as;

E = (hc)/ λ

where: E is the energy of the photon, h is the Planck's constant (6.6 x 10^{-34} Js), c is the speed of light (3 x 10^{8} m/s) and λ is the wavelength.

10.20(1.6 x 10^{-9}) = (6.6 x 10^{-34} * 3 x 10^{8})/ λ

λ = \frac{1.98*10^{-25} }{1.632*10^{-8} }

  = 1.213 x 10^{-17}

Wavelength of the photon is 1.2 x 10^{-17} m.

(c) The frequency can be determined by;

E = hf

where f is the frequency of the photon.

1.632 x 10^{-8}  = 6.6 x 10^{-34} x f

f = \frac{1.632*10^{-8} }{6.6*10^{-34} }

 = 2.47 x 10^{25} Hz

Frequency of the emitted photon is 2.47 x 10^{25} Hz.

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