What is A rounded to the nearest tenth?

Which phrase most closely characterizes a person's sense of self?

vampirchik [111]

My guess would be choice D

7 0

3 years ago

You are at the top of the Empire State Building on the 102nd floor, which is located 373 m above the ground, when your favorite

Liula [17]

Answer:

1.5 m

Explanation:

H = actual height of the superhero = ?

H₀ = height of the superhero as observed = 1.73 m

v = speed of the superhero = 0.50 c

Using the equation

$H = H_{o} \sqrt{1 - \left ( \frac{v}{c} \right )^{2}}$

Inserting the values

$H = 1.73 \sqrt{1 - \left ( \frac{0.50 c}{c} \right )^{2}}$

H = 1.5 m

3 0

3 years ago

You have decided to study the effect of loud noise on plant growth. You put one plant in a quiet room and the other plant in you

wel

The answer is B. Controlled variable.<span />

4 0

3 years ago

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A cart moving at 10 m/s is brought to a stop by the force plotted in the force-time graph shown here. Find the impulse and the a

Elena L [17]

Answer:

Impulse = 88 kg m/s

Mass = 8.8 kg

Explanation:

<u>We are given a graph of Force vs. Time. Looking at the graph we can see that the Force acts approximately between the time interval from 1sec to 4sec. </u>

Newton's Second Law relates an object's acceleration as a function of both the object's mass and the applied net force on the object. It is expressed as:

$F=ma$ Eqn. (1)

where

$F$ : is the Net Force in Newtons ( $N$ )

$m$ : is the mass ( $kg$ )

$a$ : is the acceleration ( $m/s^2$ )

We also know that the acceleration is denoted by the velocity ( $v$ ) of an object as a function of time ( $t$ ) with

$a=\frac{v}{t}$ Eqn. (2)

Now substituting Eqn. (2) into Eqn. (1) we have

$F=m\frac{v}{t}\\ \\Ft=mv$ Eqn. (3)

However since in Eqn. (3) the time-variable is present, as a result the left hand side (i.e. $Ft$ is in fact the Impulse $J$ of the cart ), whilst the right hand side denotes the change in momentum of the cart, which by definition gives as the impulse. Also from the graph we can say that the Net Force is approximately ≈ $22N$ and $t=4 sec$ (thus just before the cut-off time of the force acting).