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11Alexandr11 [23.1K]
2 years ago
10

the drama club is holding auditions for 5 different parts in a one-act play. if 9 people audition, how many ways can the roles b

e assigned?
Mathematics
1 answer:
makkiz [27]2 years ago
3 0

Answer:

The roles can be assigned in 15120 ways.

Step-by-step explanation:

The parts, which means that the order in which the people are selected is important. So we use the permutations formula to solve this question.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

P_{(n,x)} = \frac{n!}{(n-x)!}

In this question:

5 people chosen from a set of 9. So

P_{(9,5)} = \frac{9!}{(9-5)!} = 15120

The roles can be assigned in 15120 ways.

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Answer:

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The ordered pair solutions are (-\sqrt{\frac{7}{4}},0.5), (\sqrt{\frac{7}{4}},0.5), (-1,-1), and (1,-1).

Step-by-step explanation:

I'm assuming the system is \left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.:

x^2+y^2=2

x^2+(2x^2-3)^2=2

x^2+(4x^4-12x^2+9)=2

x^2+4x^4-12x^2+9=2

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(4x^2-7)(x^2-1)=0

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x=\pm\sqrt{\frac{7}{4}}

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x=\pm1

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y=2(\pm\sqrt{\frac{7}{4}})^2-3

y=2({\frac{7}{4}})-3

y=\frac{7}{2}-3

y=\frac{1}{2}

y=2x^2-3

y=2(\pm1)^2-3

y=2(1)-3

y=2-3

y=-1

Therefore, x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}} and y=-1,\frac{1}{2}

The ordered pair solutions are (-\sqrt{\frac{7}{4}},0.5), (\sqrt{\frac{7}{4}},0.5), (-1,-1), and (1,-1).

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