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11Alexandr11 [23.1K]
3 years ago
10

the drama club is holding auditions for 5 different parts in a one-act play. if 9 people audition, how many ways can the roles b

e assigned?
Mathematics
1 answer:
makkiz [27]3 years ago
3 0

Answer:

The roles can be assigned in 15120 ways.

Step-by-step explanation:

The parts, which means that the order in which the people are selected is important. So we use the permutations formula to solve this question.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

P_{(n,x)} = \frac{n!}{(n-x)!}

In this question:

5 people chosen from a set of 9. So

P_{(9,5)} = \frac{9!}{(9-5)!} = 15120

The roles can be assigned in 15120 ways.

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3 years ago
Admission for a movie is $8 for children and $12 for adults. On a certain day, 3200 people attend the movie theater and $33,040
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Let us assume the number of children attending the movie = x
Let us also assume the number of adults attending the movie = y
Cost of admission for a children in the movie = $8
Cost of admission of an adult in the movie = $12
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Total amount collected from the movie theater = $33040
Then
x + y = 3200
And
8x + 12y = 33040
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Let us first take the equation
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Now we will put the value of x in the equation
2x + 3y = 8260
2(3200 - y) + 3y = 8260
6400 - 2y + 3y = 8260
y = 8260 - 6400
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Now we will put the value of y from the above deduction in the equation
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x + 1860 = 3200
x = 3200 - 1860
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So the number of children going to the movie theater is 1340 and the number of adults going to the movie theater is 1860.
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3 years ago
Expression.<br><br> 3(4x + 3)
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Question 8 HELPPPPPPPPPPPPPP
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Answer:

it would be at 3

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<33

Step-by-step explanation:

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7 0
3 years ago
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